Question

我想按照＆＃34;十进制＆＃34;来排序字符串。数字值以及字母顺序。保持它的自然顺序。

var strArray = ["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "bbb-2.01", "aaa-11", "aaa-2.01"]

strArray.sort(function (a, b) {
    return a.localeCompare(b,undefined, {numeric: true, sensitivity: 'base'});
});

返回：

["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "aaa-2.01", "aaa-11", "bbb-2.01"]

虽然我想：

["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.01", "aaa-1.1", "aaa-2.01", "aaa-2.01", "aaa-11", "bbb-2.01"]

如何实现这一目标？即使我使用＆＃34;，＆＃34;而不是＆＃34;。＆＃34;排序是一样的。

Answer 1

您需要单独对数字和字母进行排序。

<强>样本

var strArray = ["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "bbb-2.01", "aaa-11", "aaa-2.01"]

strArray.sort(function(a, b) {
  var splitA = a.split("-");
  var splitB = b.split("-");
  if (splitA[0] == splitB[0]) {
    return (Number(splitA[1]) - Number(splitB[1]));
  } else {
    return splitA[0].localeCompare(splitB[0], undefined, {
      numeric: true,
      sensitivity: 'base'
    });
  }
});
console.log(strArray);

Answer 2

您可以将parameters中的标记ignorePunctuation设置为true。

var array = ["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "bbb-2.01", "aaa-11", "aaa-2.01"]

array.sort(function(a, b) {
    return a.localeCompare(b, undefined, { ignorePunctuation: true, numeric: true, sensitivity: 'base' });
});

console.log(array);

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JavaScript localeCompare排序不好[＆＃34; aaa-1.0＆＃34;，＆＃34; aaa-1.1＆＃34;，＆＃34; aaa-1.01＆＃34;，＆＃34; AAA-11＆＃34;＆＃34; AAA-2.01＆＃34;]

2 个答案: