Question

我正在使用KoGrid插件来获得具有选择复选框的淘汰网格。到目前为止，我有以下代码。

    function columnDefsVM() {
    var self = this;
    this.myData = ko.observableArray(GlobalJson);
    this.mySelectedData = ko.observableArray(SelectedJson);

    this.gridOptions = {
        data: self.myData,
        columnDefs: [{ field: 'TestEventId', displayName: 'Name' }],
        selectedItems: self.mySelectedData,
        enablePaging: false,
    };
}
ko.applyBindings(new columnDefsVM());

我只是想知道如何访问selectedItems属性，以便将所选值传递给ajax调用？

或者我不能这样做，必须使用afterSelectionChange选项手动将所选的ID推送到数组吗？

Answer 1

在gridOptions中，您传递了对mySelectedData可观察数组的引用，以用作SelectedItems，因此您应该可以使用原始mySelectedData }变量而不是SelectedItems;他们是等同的。当网格选择发生变化时，mySelectedData将会更新。

＆＃13;

function columnDefsVM() {
    var self = this;
    this.myData = ko.observableArray([
    	{TestEventId: 1, Name: 'Object 1'},
    	{TestEventId: 2, Name: 'Object 2'},
    	{TestEventId: 3, Name: 'Object 3'},
    ]);
    this.mySelectedData = ko.observableArray([]);

    this.gridOptions = {
        data: self.myData,
        columnDefs: [{ field: 'TestEventId', displayName: 'Name' }],
        selectedItems: self.mySelectedData,
        enablePaging: false,
    };
}
ko.applyBindings(new columnDefsVM());

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/knockout/3.4.2/knockout-min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdn.jsdelivr.net/gh/Knockout-Contrib/KoGrid@2.0.6/koGrid-2.0.6.debug.js"></script>
<link href="https://cdn.jsdelivr.net/gh/Knockout-Contrib/KoGrid@2.0.6/KoGrid.css" rel="stylesheet" />

<label>mySelectedData: </label><span data-bind="text: ko.toJSON(mySelectedData)"></span>
<br/>
<br/>
<div style="height:200px;" data-bind="koGrid: gridOptions"></div>

＆＃13;

KoGrid行选择绑定

1 个答案: