Question

是否可以循环遍历数组并使用passwd值从ord[i]中选择一个字符？代码

             String ordinal = vars.get("ordinal");
             String[] ord = ordinal.split(",");
             log.info(ord[0]);

             String passwd = vars.get("password");
             requiredOrd = new ArrayList();
             for(int i=0; i< ord.length; i++)
             {

                    requiredOrd.add((passwd.charAt(ord[i])));

              }

          log.info(requiredOrd[0]);

返回错误消息，如下所示：

2017-10-23 10:23:26,270错误o.a.j.u.BeanShellInterpreter：调用bsh方法时出错：eval源文件：内联评估：String ordinal = vars.get("ordinal"); String[] ord = ordinal.split(","); log.inf . . . '' : Error in method invocation: Method charAt( java.lang.String ) not found in class'java.lang.String' 2017-10-23 10:23:26,270 WARN o.a.j.e.BeanShellPostProcessor: Problem in BeanShell script: org.apache.jorphan.util.JMeterException: Error invoking bsh method: eval Sourced file: inline evaluation of: String ordinal = vars.get（“ordinal”）; String [] ord = ordinal.split（“，”）; log.inf。。。 ''：方法调用出错：在类'java.lang.String'中找不到方法charAt（java.lang.String）

Answer 1

使用Beanshell，您可以使用String方法charAt，它返回每个索引的字符。

数组中的索引从0开始，因此更改为i = 0和passwd.length()调用：

for(int i=0;i<passwd.length(); i++) {
  log.info(passwd.charAt(i))

Answer 2

因为JMeter中的JMeter 3.1 it is recommended to use JSR223 Test Elements and Groovy language for any form of scripting所以请考虑切换到Groovy语言：

它更符合Java
has many enhancements on top of Java core SDK
和Groovy performance is much better being compared to Beanshell

迭代字符串的相关代码如下：

def password = 'foo'
for (char c : password.toCharArray()) {
    log.info('Current char: ' + c)
}

Answer 3

id_ALL =“ fbe9ca5c-942b-48d8-9ffd-5f92ae64437a”， “ 4f90ef0f-c317-47ea-9013-53729477c379”， “ 98fe94ae-7e1b-42bb-8c2f-cae0f31105a0”， “ b3f8ed32-e273-41d8-8caf-2024feeccd8c”

StatusMFP_ALL="true","true","false","false"

StatusIwb_ALL= "true", "false", "false", "true"


String[] ids = {${id_ALL}};

String[] StatusM = {${StatusMFP_ALL}};

String[] StatusI = {${StatusIwb_ALL}};

//To get array length

int count = Integer.parseInt(vars.get("id_matchNr"));
log.info( "countest" + vars.get("id_matchNr"));

ArrayList c = new ArrayList();

    for (int i = 0; i <=count-1; i++)
       {
         String M=StatusM[i];
         String I=StatusI[i];
              if(M=="true" || I=="true" )      
                {                  
                    String x=ids[i];                
                    c.add(x);                                                                                                         
                }      
      }            
        for (int i = 0; i < c.size(); i++) 
        {
              log.info(c.get(i));           
        }
        log.info(c.get(0));

如何在jmeter 3.2中的beanshell脚本中循环遍历数组

3 个答案: