我有SWIFT代码,我已经映射了一组具有相同数量元素的列表,其中1是一个int列表,它们按降序映射。这是我的SWIFT代码......
class Video
{
let videoID: String
let rank: Int
let title: String
let imageString: String
init(videoID: String, rank: Int, title: String, imageString: String)
{
self.videoID = videoID
self.rank = rank
self.title = title
self.imageString = imageString
}
}
var videos = [Video]()
videos.sort { $0.rank < $1.rank }
self.vidTitleArray = videos.map { $0.title }
self.vidRankArray = videos.map { $0.rank }
self.vidIdArray = videos.map { $0.videoID }
self.vidImageArray = videos.map { $0.imageString }
这就是我在Flutter的地方,但我在前进中遇到错误......
class videos{
String videoId;
int rank;
String title;
String imageString;
videos(this.videoId, this.rank, this.title, this.imageString);
}
如何从类构造函数中创建list
,然后按照降序映射到排名重新排列所有元素?
*****选项*****
这是我的代码,不使用Video
类。我使用SplayTreeMap
正确排名,但如果Value
始终相同,则只返回1个节点。有没有办法映射以Value
降序的所有4张地图?
映射myMap = event.data.snapshot.value; //存储每张地图
var titles = myMap.values;
List onesTitles = new List();
List onesIds = new List();
List onesImages = new List();
List onesRank = new List();
for (var items in titles) {
onesTitles.add(items['vidTitle']);
onesIds.add(items['vidId']);
onesImages.add(items['vidImage']);
onesRank.add(items['Value']);
}
names = onesTitles;
ids = onesIds;
numbers = onesRank;
vidImages = onesImages;
答案 0 :(得分:3)
您可以使用List.sort()
来实现此目的,我创建了一个自定义示例,其中我对Videos
类的3个实例进行了硬编码,然后在List
的构建方法中添加了它们按升序排列。使用List.sort()
和compareTo
,我可以按降序重新排列它们。
List<Videos> myList = [_firstVideos, _secondVideos, _thirdVideos];
sort() {
for (var video in myList) {
print(video.rank); ///prints 1 2 3
}
myList.sort((y, x) => x.rank.compareTo(y.rank));
for (var video in myList) {
print(video.rank); ///prints 3 2 1
}
}
...
import 'package:flutter/material.dart';
void main(){
runApp(new MaterialApp(home: new MyApp(),));
}
class MyApp extends StatelessWidget {
Videos _firstVideos = new Videos(
videoId: "0001",
rank: 1,
title: "My First Video",
imageString: "My First Image",
);
Videos _secondVideos = new Videos(
videoId: "0002",
rank: 2,
title: "My Seocnd Video",
imageString: "My Second Image",
);
Videos _thirdVideos = new Videos(
videoId: "0003",
rank: 3,
title: "My Third Video",
imageString: "My Third Image",
);
@override
Widget build(BuildContext context) {
List<Videos> myList = [_firstVideos,_secondVideos,_thirdVideos];
sort()
{
myList.sort((y,x)=>x.rank.compareTo(y.rank));
print(myList[0].title);
}
return new Scaffold(
body: new Center(
child: new FlatButton(onPressed: sort, child: new Text("Sort")),
),
);
}
}
class Videos{
String videoId;
int rank;
String title;
String imageString;
Videos({this.videoId, this.rank, this.title, this.imageString});
}