Question

在开发过程中，我遇到了urlManager的一个问题。

我的SiteController包含＆＃34;类别＆＃34;动作。

public function actionCategory($id = null, $city = null, $location = null)
{
   echo $id;
   echo $city;
   echo $location;
}

可以与此操作一起使用的所有可能组合：

id, city, location = null
id, city = null, location
id, city = null, location = null
id = null, city = null, location = null
id = null, city = null, location

我不知道如何在UrlManager中编写规则，之后按下链接后我会在变量中得到以下值：

<h4><?= Html::a('ID City', ['/site/category', 'id' => 'barbershop', 'city' => 'Praha'], ['class' => 'btn btn-primary']) ?></h4>
The return value from "category" action:

id = 'barbershop'
city = 'Praha'
location = ''

<h4><?= Html::a('ID Location', ['/site/category', 'id' => 'barbershop', 'location' => '23,65'], ['class' => 'btn btn-primary']) ?></h4>
The return value from "category" action:

id = 'barbershop'
city = ''
location = '23,65'

<h4><?= Html::a('ID', ['/site/category', 'id' => 'barbershop'], ['class' => 'btn btn-primary']) ?></h4>
The return value from "category" action:

id = 'barbershop'
city = ''
location = ''

<h4><?= Html::a('City', ['/site/category', 'city' => 'Praha'], ['class' => 'btn btn-primary']) ?></h4>
The return value from "category" action:

id = ''
city = 'Praha'
location = ''

<h4><?= Html::a('Location', ['/site/category', 'location' => '14,23'], ['class' => 'btn btn-primary']) ?></h4>
The return value from "category" action:

id = ''
city = ''
location = '14,23'

你想帮我解决这个问题吗？

Answer 1

根据您的要求，您只需为Controller和操作名称设置规则。所有其他字段都通过$ _GET传递。并且您可以使用Yii::$app->getRequest()->getQueryParam('param')方法获取它们。

对于您的网址，您可以使用常规规则，例如

'urlManager' => [
        'enablePrettyUrl' => true,
        'showScriptName' => false,
        'rules' => [
            '<controller:\w+>/<id:\d+>' => '<controller>/view',
            '<controller:\w+>/<action:\w+>/<id:\d+>' => '<controller>/<action>',
            '<controller:\w+>/<action:\w+>' => '<controller>/<action>',
        ],
    ],

Yii2，rounte

1 个答案: