遍历printf列表

Question

我有一个prinf函数列表，我想知道如何遍历它们。

#include <stdio.h>


void N()
{
    int count;
    count += count;
}

int main()

{
   int pfReturnCount = 0;

   pfReturnCount = printf("#####.00000000000.......00000...00000#### \n");
   pfReturnCount = printf("#####..000.....000......000000...000.#### \n");
   pfReturnCount = printf("#####..000.....000......000.000..000.#### \n");
   pfReturnCount = printf("#####..0000000000.......000..000.000.#### \n");
   pfReturnCount = printf("#####..000.....000......000...000000.#### \n");
   pfReturnCount = printf("#####..000.....000......000....00000.#### \n");
   pfReturnCount = printf("#####.00000000000......00000...00000.#### \n");

   N(pfReturnCount);
   printf("data value after calling the N funtion is %d\n",pfReturnCount);

   return (0);
}

我得到它给我第一个printf的值，但我不知道如何遍历整个列表，所以我可以总结我在所有printf函数中的字符总数。

Answer 1

只需用+ =

替换=

#include <stdio.h>


void N()
{
    int count;
    count += count;
}

int main()

{
   int pfReturnCount = 0;

   pfReturnCount += printf("#####.00000000000.......00000...00000#### \n");
   pfReturnCount += printf("#####..000.....000......000000...000.#### \n");
   pfReturnCount += printf("#####..000.....000......000.000..000.#### \n");
   pfReturnCount += printf("#####..0000000000.......000..000.000.#### \n");
   pfReturnCount += printf("#####..000.....000......000...000000.#### \n");
   pfReturnCount += printf("#####..000.....000......000....00000.#### \n");
   pfReturnCount += printf("#####.00000000000......00000...00000.#### \n");

   N(pfReturnCount);
   printf("data value after calling the N funtion is %d\n",pfReturnCount);

   return (0);
}

Answer 2

您可以将每一行推送到一个字符串数组，然后只需获取数组中每个元素的长度。