Question

我试图用Python编写Blackjack纸牌游戏。在玩家类中，我想定义一个循环，要求玩家决定“击中”＃34;或者＆＃34;站立＆＃34; （二十一点规则）。除非输入正确（对于立场是“S＆＃39;对于点击”而言是“H＆＃39;”），循环需要循环直到玩家输入这两个选项中的一个。

以下是此特定部分的代码：

while True:
    try:
        D = input('What is your decision, stand or hit? [press S for stand and H for hit]: ')
        if D in ['S', 'H'] is False:
            1/0
    except:
        print('Incorrect input, please try again (S for stand and H for hit)!')
        continue
    else:
        if D == 'S':
            print('OK, you decided to stand!')
        else:
            print('OK, you decided to hit. You will receive a 3rd card!')
        break

所以我的想法是，除非做出正确的决定（＆＃39; S＆＃39; H＆＃39; H＆＃39;），否则会产生错误，但到目前为止，代码并不起作用正确地......我认为有一个小小的故障......

任何提案？亲切的问候，

→

Answer 1

你应该写：

if D not in ['S', 'H']:

整个代码会更短，更易读，没有例外：

while True:
    D = input('What is your decision, stand or hit? [press S for stand and H for hit]: ')
    if D not in ['S', 'H']:
        print('Incorrect input, please try again (S for stand and H for hit)!')
        continue
    else:
        if D == 'S':
            print('OK, you decided to stand!')
        else:
            print('OK, you decided to hit. You will receive a 3rd card!')
        break

Answer 2

那里不需要例外，你可以这样做：

while True:    # infinite loop
    D = input('What is your decision, stand or hit? [press S for stand and H for hit]: ')
    if D == "S":
        #do some
        break 
    elif D == "H":
        # Hit some.
        break
    else:
        print('Incorrect input, please try again (S for stand and H for hit)!')
        break

错误处理所需的输入

2 个答案: