1 .list-of-links.component.html
<table class="table">
<thead>
<tr>
<th>
№
</th>
<th>
Logo
</th>
<th style="text-align: center">
Link
</th>
<th>
Action
</th>
</tr>
</thead>
<tbody>
<tr class="active" *ngFor="let link of list ; let i=index">
<td>
{{i+1}}
</td>
<td>
<img *ngIf="link.domain ==='rutracker.org'" src="https://lh4.ggpht.com/S0dUXg8MuXp4_AUaIvmO5c-qJ5bH_vKtpdI5B7gHhiTAJF-t-UJYR9uuAPF7qN4fUA=w300" height="30" width="30">
</td>
<td style="text-align: center">
<a href="{{link.torrentLink}}" >{{link._linkID.linkTitle}}</a>
</td>
<td>
<button (click)="onSubmitForDelete(this.list[i]._linkID._id)" >delete</button>
</td>
</tr>
</tbody>
</table>
2。这个html的组件
private list ;
constructor(private listOfLinks : ListOfLinks) {
}
async ngOnInit() {
this.list = await this.listOfLinks.getLinksList();
}
async onSubmitForDelete (data){
try{
this.listOfLinks.deleteLink(data);
}catch(err){
return err;
}
}
deleteLink (_linkID){ return this.http.get('/api/delete/'+_linkID).toPromise() }
正如你在上面的组件中看到的,我有一些数据列表..我可以从这个列表中删除数据(我有一些服务可以做到这一点)。但我无法理解如何在删除此列表中的任何组件后刷新我的表
答案 0 :(得分:1)
async onSubmitForDelete (data){
try{
await this.listOfLinks.deleteLink(data);
this.list = await this.listOfLinks.getLinksList();
}catch(err){
return err;
} }
- &GT;&GT;希望它会帮助某人)感谢您帮助&#34; kemsky&#34;和&#34;丹尼斯&#34;
答案 1 :(得分:0)
async onSubmitForDelete (data){
try{
this.listOfLinks.deleteLink(data).then(() => {
// Find index of "data" in your "list" and delete that element from your list yourself
// OR
// request the whole list again from your service and populate "list" again
};
}catch(err){
return err;
}
}