添加subscribeOn()正在改变observable的返回类型

时间:2017-10-19 11:32:10

标签: android kotlin rx-kotlin

我遇到了一个我很难理解的奇怪问题。我编写了一些代码来创建一个可调用的observable。它编译得很好,但是一旦我为它指定了一个调度程序,它就会改变返回类型并且不会编译。

这是没有subscribeOn(编译)的代码:

/**
 * Gets all the room bookings for the specified day
 */
override fun getRoomBookingsForDay(date: Date): Observable<Collection<Model.RoomBooking>> =
        Observable.fromCallable {
            Realm.getDefaultInstance().use { realm ->
                // Get all the bookings that begin and end within the specified date
                val dbRoomBookings =
                        realm.where(DBRoomBooking::class.java)
                                .greaterThan("timeFromUtc", date)
                                .lessThan("timeToUtc", date)
                                .findAllSorted("timeFromUtc")

                if (dbRoomBookings.isEmpty()) {
                    emptyList()
                } else {
                    dbRoomBookings.asSequence().map { dbRoomBooking ->
                        makeRoomBookingModel(dbRoomBooking)
                    }.filterNotNull().toList()
                }
            }
        }

以下是带有subscribeOn的代码(它没有编译):

/**
 * Gets all the room bookings for the specified day
 */
override fun getRoomBookingsForDay(date: Date): Observable<Collection<Model.RoomBooking>> =
        Observable.fromCallable {
            Realm.getDefaultInstance().use { realm ->
                // Get all the bookings that begin and end within the specified date
                val dbRoomBookings =
                        realm.where(DBRoomBooking::class.java)
                                .greaterThan("timeFromUtc", date)
                                .lessThan("timeToUtc", date)
                                .findAllSorted("timeFromUtc")

                if (dbRoomBookings.isEmpty()) {
                    emptyList()
                } else {
                    dbRoomBookings.asSequence().map { dbRoomBooking ->
                        makeRoomBookingModel(dbRoomBooking)
                    }.filterNotNull().toList()
                }
            }
        }.subscribeOn(AndroidRealmSchedulers.realmThread())

编译时错误消息是:

Type mismatch.
Required: Observable<Collection<Model.RoomBooking>>
Found: Observable<List<Model.RoomBooking>!>!

当然,指定调度程序不应该更改正在返回的类型?有什么想法吗?

1 个答案:

答案 0 :(得分:1)

我认为您必须使用return-type定义协方差:

override fun getRoomBookingsForDay(date: Date): Observable<out Collection<Model.RoomBooking>>

使用out T与Java中的? extends T相同。

或者,您可以确保仅使用Collection。在您的第一个示例中,Observable.fromCallable()的返回类型由fun的返回类型推断,而第二个示例中的Callable的返回类型推断出Observable.fromCallable<Collections<Model.RoomBooking>> { ... } 的返回类型。所以直接申报:

bundle.putString("Types", types.toString());