Question

学习Zend3框架。在一个示例Zend3项目上工作，我必须创建一个Model子类型。

我有以下Book.php模型：

<?php

namespace Products\Model;

class Book
{
    public $id;
    public $author;
    public $title;
    public $isbn;



    public function exchangeArray(array $data)
    {
        $this->id     = !empty($data['id']) ? $data['id'] : null;
        $this->author = !empty($data['author']) ? $data['author'] : null;
        $this->title  = !empty($data['title']) ? $data['title'] : null;
        $this->isbn  = !empty($data['isbn']) ? $data['isbn'] : null;
    }

    public function getArrayCopy()
    {
        return [
            'id'     => $this->id,
            'author' => $this->author,
            'title'  => $this->title,
            'isbn'  => $this->isbn,

        ];
    } 

}

现在我必须创建：

＆＃34; Book＆＃34;的子类型这被称为＆＃34; Thriller＆＃34;，继承自＆＃34; Book＆＃34;并有一个名为＆＃34; excitement_factor＆＃34;

的附加属性

，同时：

它在数据库和模型中正确反映了这种关系，我应该：

最后确保数据库完整性：

实现足够的表模型函数来检索，保存和删除＆＃34;惊悚片，对所有查询使用ORM风格

我该怎么做？

Thriller是否应该使用新字段扩展Book类？我如何在Zend3中执行此操作？基础表怎么样？ Zend会为Thriller创建新表吗？我必须调整哪些文件？

使用ORM Style方法是指fetchAll（），fetchOneBy（）等？

谢谢，

更新1：

My Book表格如下：

CREATE TABLE book (id INT AUTO_INCREMENT NOT NULL, author varchar(100) NOT NULL, title varchar(100) NOT NULL, isbn varchar(100) NOT NULL, type ENUM("Thriller") NOT NULL, PRIMARY KEY(id))

创建了第二个表格Thriller：

CREATE TABLE thriller
(
    id INT NOT NULL,
    book INT NOT NULL,
    excitement_factor VARCHAR(100) NOT NULL,
    PRIMARY KEY(id),
    FOREIGN KEY(book) REFERENCES book(id)
)

两者都有TableGateways。

模型如下：

cat Book.php 
<?php

namespace Products\Model;

class Book
{
    public $id;
    public $author;
    public $title;
    public $isbn;

    private $inputFilter;

    public function exchangeArray(array $data)
    {
        $this->id     = !empty($data['id']) ? $data['id'] : null;
        $this->author = !empty($data['author']) ? $data['author'] : null;
        $this->title  = !empty($data['title']) ? $data['title'] : null;
        $this->isbn  = !empty($data['isbn']) ? $data['isbn'] : null;
    }

    public function getArrayCopy()
    {
        return [
            'id'     => $this->id,
            'author' => $this->author,
            'title'  => $this->title,
            'isbn'  => $this->isbn,

        ];
    } 

}
cat BookTable.php 
<?php

namespace Products\Model;

use RuntimeException;
use Zend\Db\TableGateway\TableGatewayInterface;

class BookTable
{
    private $tableGateway;

    public function __construct(TableGatewayInterface $tableGateway)
    {
        $this->tableGateway = $tableGateway;
    }

    public function fetchAll()
    {
        return $this->tableGateway->select();
    }

    public function getBook($id)
    {
        $id = (int) $id;
        $rowset = $this->tableGateway->select(['id' => $id]);
        $row = $rowset->current();
        if (! $row) {
            throw new RuntimeException(sprintf(
                'Could not find row with identifier %d',
                $id
            ));
        }

        return $row;
    }

    public function saveBook(Book $book)
    {
        $data = [
            'author' => $book->author,
            'title'  => $book->title,
            'isbn'  => $book->isbn,

        ];

        $id = (int) $book->id;

        if ($id === 0) {
            $this->tableGateway->insert($data);
            return;
        }

        if (! $this->getBook($id)) {
            throw new RuntimeException(sprintf(
                'Cannot update book with identifier %d; does not exist',
                $id
            ));
        }

        $this->tableGateway->update($data, ['id' => $id]);
    }

    public function deleteBook($id)
    {
        $this->tableGateway->delete(['id' => (int) $id]);
    }
}

cat Thriller.php 
<?php

namespace Products\Model;

class Thriller
{
    public $id;
    public $book;
    public $excitement_factor;

    private $inputFilter;

    public function exchangeArray(array $data)
    {
        $this->tid     = !empty($data['id']) ? $data['id'] : null;
        $this->book = !empty($data['book']) ? $data['book'] : null;
        $this->excitement_factor = !empty($data['excitement_factor']) ? $data['excitement_factor'] : null;
    }

    public function getArrayCopy()
    {
        return [
            'id'     => $this->id,
            'book' => $this->book,
            'excitement_factor' => $this->excitement_factor,

        ];
    } 

}

cat ThrillerTable.php 
<?php

namespace Products\Model;

use RuntimeException;
use Zend\Db\TableGateway\TableGatewayInterface;

class ThrillerTable
{
    private $tableGateway;

    public function __construct(TableGatewayInterface $tableGateway)
    {
        $this->tableGateway = $tableGateway;
    }

    public function fetchAll()
    {
        return $this->tableGateway->select();
    }

    public function getThriller($id)
    {
        $id = (int) $id;
        $rowset = $this->tableGateway->select(['id' => $id]);
        $row = $rowset->current();
        if (! $row) {
            throw new RuntimeException(sprintf(
                'Could not find row with identifier %d',
                $id
            ));
        }

        return $row;
    }

    public function saveThriller(Thriller $thriller)
    {
        $data = [
            'book' => $thriller->book,
            'excitement_factor'  => $thriller->excitement_factor,


        ];

        $id = (int) $thriller->id;

        if ($id === 0) {
            $this->tableGateway->insert($data);
            return;
        }

        if (! $this->getThriller($id)) {
            throw new RuntimeException(sprintf(
                'Cannot update thriller with identifier %d; does not exist',
                $id
            ));
        }

        $this->tableGateway->update($data, ['id' => $id]);
    }

    public function deleteThriller($id)
    {
        $this->tableGateway->delete(['id' => (int) $id]);
    }
}

在我的控制器中添加Book，我只是这样做：

public function addBookAction()
    {
        $form = new BookForm();
        $form->get('submit')->setValue('Add');

        $request = $this->getRequest();

        if (! $request->isPost()) {
            return ['form' => $form];
        }

        $bookForm = new BookForm();
        $form->setInputFilter($bookForm->getInputFilter());
        $form->setData($request->getPost());

        if (! $form->isValid()) {
            return ['form' => $form];
        }

        $bookModel = new Book();

        $bookModel->exchangeArray($form->getData());


        $this->book->saveBook($bookModel);
        return $this->redirect()->toRoute('product');
    }

如何立即添加惊悚片？

public function addThrillerAction()
{
    // ???
}

Answer 1

＆＃34; Thriller＆＃34;必须是一个书对象？也许它可以是一个＆＃34;类型＆＃34;书的对象。在这种方法中，书籍对象具有属性＆＃34;类型＆＃34;当然＆＃34; addGenre / removeGenre / hasGenre / getGenres＆＃34;方法。我的意思是每本书都有不止一种类型。您还可以将所有类型保留在表格中，获取它们并填充表单。顺便说一句，你可以对它们运行查询。数据透视表足以保持书籍和流派的关系。

Zend3模型子类型

1 个答案: