我需要将较小的3D矩阵放入更大的3D矩阵中。用一个例子解释:
假设我有以下3D矩阵:
%A is the big matrix
A(:,:,1)=[ 0.3545 0.8865 0.2177
0.9713 0.4547 0.1257
0.3464 0.4134 0.3089];
A(:,:,2)=[ 0.7261 0.0098 0.7710
0.7829 0.8432 0.0427
0.6938 0.9223 0.3782];
A(:,:,3) = [0.7043 0.2691 0.6237
0.7295 0.6730 0.2364
0.2243 0.4775 0.1771];
%B is the small matrix
B(:,:,1) = [0.3909 0.5013
0.0546 0.4317];
B(:,:,2) =[0.4857 0.1375
0.8944 0.3900];
B(:,:,3) =[0.7136 0.3433
0.6183 0.9360];
现在将B放入A中:使用第一维:[1 3],第二维[2 3],并对A的[1,2,3]页执行此操作。对于给定的矩阵,放置这些值将导致:
NewA(:,:,1) = [ 0.3545 0.3909 0.5013 % putting the value of %B(1,:,1)
0.9713 0.4547 0.1257
0.3464 0.0546 0.4317; % putting the value of %B(2,:,1)
NewA(:,:,2)=[ 0.7261 0.4857 0.1375 % putting the value of %B(1,:,2)
0.7829 0.8432 0.0427
0.6938 0.8944 0.3900]; % putting the value of %B(2,:,2)
NewA(:,:,3) = [0.7043 0.7136 0.3433 % putting the value of %B(1,:,3)
0.7295 0.6730 0.2364
0.2243 0.6183 0.9360]; % putting the value of %B(2,:,3)
我不一定将方形矩阵作为3D页面,A
放入B
的大小也可能不同。但矩阵将永远是3D。以上只是一个小例子。我实际拥有的尺寸与A一样大 - > [500,500,5]和B为 - > [350,350,4]。
这是sub2ind
对2D矩阵所做的事情,但我还不能用于3D矩阵。
类似的东西:
NewA = A;
NewA(sub2ind(size(A), [1 3], [2 3], [1 2 3])) = B;
但它给出了:
Error using sub2ind (line 69)
The subscript vectors must all be of the same size.
我该怎么做?
答案 0 :(得分:1)
您不需要sub2ind
,只需直接分配:
newA(1,2:3,:)=B(1,:,:)
如果您想使用sub2ind
,则需要为要替换的每个元素指定3个维度中的每个维度:
dim1A=[1 1 1 1 1 1]; % always first row
dim2A=[2 3 2 3 2 3]; % second and third column, for each slice
dim3A=[1 1 2 2 3 3]; % two elements from each slice
newA(sub2ind(size(A),dim1A,dim2A,dim3A))=B(1,:,:)
newA(:,:,1) =
0.3545 0.3909 0.5013
0.9713 0.4547 0.1257
0.3464 0.4134 0.3089
newA(:,:,2) =
0.7261 0.4857 0.1375
0.7829 0.8432 0.0427
0.6938 0.9223 0.3782
newA(:,:,3) =
0.7043 0.7136 0.3433
0.7295 0.6730 0.2364
0.2243 0.4775 0.1771