Question

我尝试重命名替换＆＃39; VV＆＃39;与VV

alist = ["py'VV'1.File.md",
 "py'VV'3.Database.md",
 "py'VV'Projects.md",
 "py'VV'2.Input.md"]

我想要的输出：

newlist = ["pyVV1.File.md",
 "pyVV3.Database.md",
 "pyVVProjects.md",
 "pyVV2.Input.md"]

我的解决方案

[i.replace("'VV'",'VV') for i in alist]
Out[158]: ['pyVV1.File.md', 'pyVV3.Database.md', 'pyVVProjects.md', 'pyVV2.Input.md']

如何通过魔法访问处理它以自动消除引用' '。

例如：

In [163]: eval('str')
Out[163]: str

Answer 1

尝试以下代码

[x.replace("'", "") for x in alist]
#O/p: ['pyVV1.File.md', 'pyVV3.Database.md', 'pyVVProjects.md', 'pyVV2.Input.md']

你的也是正确的，但是如果你想要替换列表中每个字符串的任何单引号，那么上面应该可行。（它将取代＆＃34;＆＃39; VV＆＃39;＆＃34;＆＃34; VV＆＃34;以及＆＃34;＆＃39; anychar＆＃39;＆＃34;到＆＃ 34; anychar＆＃34;）。希望它有所帮助。

Answer 2

您可以使用正则表达式删除引号：

import  re

alist = ["py'VV'1.File.md",
 "py'VV'3.Database.md",
 "py'Pass'Projects.md",
 "py'VX'2.Input.md"]

pattern = r'\'(.*?)\''
blist = [re.sub(pattern, lambda x : x.group(1), s) for s in alist]

print(blist)

从多个字符串中删除引号

2 个答案: