即使GPIO FD发生变化,也不会返回

时间:2017-10-19 08:01:34

标签: c linux embedded-linux file-descriptor poll-syscall

我试图在改变状态时尝试读取GPIO值。

/sys/class/gpio/gpio499/value

我已将/sys/class/gpio/gpio499/edge设为两者

我正在尝试使用 poll 命令在一个单独的线程中监视值的变化。以下是代码段:

void PIN_gpio_poll(size_t gpio)     //GPIO 499
{
        char path[30];
        char cValue;
        int fd;
        int ret_poll;
        int ret_read;
        struct pollfd pollfd;
        int i;

        pollfd.events = POLLPRI | POLLERR; /* look for GPIO status change. */


        snprintf(path, 30, PHDRIVER_LINUX_CFG_DIR "/gpio%u/value", gpio);
        fd = open(path, O_RDONLY);
        if (fd == -1)
        {
                printf("Gpio_poll _ERROR\r\n");
        }

        pollfd.fd = fd;

        ret_read = read(pollfd.fd, &cValue, 1);    // Dummy Read to clear

        while (1)
        {
                lseek(fd, 0, SEEK_SET);
                ret_read = read(fd, &cValue, 1);
                printf("Value=%c, RET READ=%d\n",cValue,ret_read);
//              ret_poll = poll( &pollfd, 1, -1 );
                ret_poll = poll( &pollfd, 1, 10000 );  //10sec timeout

                printf("******REVENTS=%x\n",pollfd.revents);
                if( ret_poll == -1 )
                {
                        printf("Gpio_poll poll failed\r\n");
                        close(fd);
                }else{
//                      if (pollfd.revents & POLLPRI )
                        {
                                lseek(fd, 0, SEEK_SET);
                                ret_read = read(pollfd.fd, &cValue, 1);
                                if(ret_read > 0)
                                {
                                    printf("Cvalue = %c\n",cValue);
                                }
                        }

                }
        }
}

我面临的问题是如果我将事件设置为 POLLIN ,则poll会立即返回。这是理解的,因为总是要在(0或1)GPIO中读取数据。我提到https://www.kernel.org/doc/Documentation/gpio/sysfs.txt并将事件设置为POLLPRI | POLLERR。但是在此方法中,轮询仅在超时后返回。当GPIO的值发生变化时,它不会返回。有什么我想念的诀窍吗?我还将/sys/class/gpio/gpio499/edge设置为上升,下降,但似乎没有任何效果。

编辑: 这是grep -r . /sys/class/gpio/gpio499

的输出
/sys/class/gpio/gpio499/edge:both
/sys/class/gpio/gpio499/power/control:auto
/sys/class/gpio/gpio499/power/runtime_active_time:0
grep: /sys/class/gpio/gpio499/power/autosuspend_delay_ms: Input/output error
/sys/class/gpio/gpio499/power/runtime_status:unsupported
/sys/class/gpio/gpio499/power/runtime_suspended_time:0
/sys/class/gpio/gpio499/value:1
/sys/class/gpio/gpio499/active_low:0
/sys/class/gpio/gpio499/direction:in

注意:我想检测1到0之间的值。

1 个答案:

答案 0 :(得分:0)

函数:poll()不起作用,因为发布的代码是期望的。

建议:1)读取文件以获取当前输入值。 2)执行旋转循环,读取值,直到值改变,类似于:

readbytes = read( fd, &cValue, 1 );  
while( readbytes > 0 )
{  
    if( (off_t)-1 == lseek(fd, 0, SEEK_SET) )
    { // then lseek failed
        perror( "lseek failed" );
        exit( EXIT_FAILURE );
    }

    // implied else, lseek successful

    readbytes = read(fd, &new_cValue, 1);
    if( 0 >= readbytes )
    { 
        perror( "read failed" );
        exit( EXIT_FAILURE );
    }

    // implied else, read successful

    if( cValue != new_cValue )
    { // then state changed
        cValue = new_cValue;
        break;
    }
}

此循环确实会消耗更多CPU周期,但应该可以正常工作