Question

我试图只在特定的用户名表中放置一个用户名。

现在它将所有用户名放在表格中。

代码：

$top_user_array = array('user1', 'user2', 'user3', 'user4');

$top_user_array = join("', '", $top_user_array);

$query = "SELECT * FROM users WHERE username IN ('{$top_user_array}')";
$send_query = mysqli_query($connection, $query);

while ($row = mysqli_fetch_assoc($send_query)) {
    $author = $row['username'];

    if(isset($_POST['create_sub'])) {

        $username = $_SESSION['username'];

        $query = "UPDATE users SET user_subs = CONCAT(IFNULL(user_subs,''), '{$username}' ',') WHERE username = '{$author}' ";

        $create_user_sub = mysqli_query($connection, $query);

        confirmQuery($create_user_sub);

        $query = "UPDATE users SET user_subscriptions = CONCAT(IFNULL(user_subscriptions,''), '{$author}' ',') WHERE username = '{$username}' ";

        $create_user_subscription = mysqli_query($connection, $query);

        confirmQuery($create_user_subscription);

        echo "Subscribed";
    }

    echo '<form action="" method="post" enctype="multipart/form-data">
            <div class="form-group">
                <button type="submit" name="create_sub" class="btn btn-primary">Subscribe To '. $author; echo ' <i class="fa fa-users" aria-hidden="true"></i></button>
            </div>
        </form>';
}

基本示例：

如果＆＃34;主要用户＆＃34;订阅user1它会将所有用户放入＆＃34;主要用户＆＃34; user_subscriptions行而不只是将特定的用户名放在那里。

主用户订阅user1后数据库的外观

如果主要用户订阅了user1，它应该如何实际

使用@Kodoyosa后

这是得到我想要的结果的代码：

$top_user_array = array('user1', 'user2', 'user3', 'user4');

$top_user_array = join("', '", $top_user_array);

$query = "SELECT * FROM users WHERE username IN ('{$top_user_array}')";
$send_query = mysqli_query($connection, $query);

while ($row = mysqli_fetch_assoc($send_query)) {
    $author = $row['username'];

    $author_u = str_replace(' ', '_', $author);    

    if(isset($_POST["create_sub_{$author_u}"])) {

        $username = $_SESSION['username'];

        $query = "UPDATE users SET user_subs = CONCAT(IFNULL(user_subs,''), '{$username}' ',') WHERE username = '{$author}' ";

        $create_user_sub = mysqli_query($connection, $query);

        confirmQuery($create_user_sub);

        $query = "UPDATE users SET user_subscriptions = CONCAT(IFNULL(user_subscriptions,''), '{$author}' ',') WHERE username = '{$username}' ";

        $create_user_subscription = mysqli_query($connection, $query);

        confirmQuery($create_user_subscription);

        echo "Subscribed";
    }

    echo '<form action="" method="post" enctype="multipart/form-data">
            <div class="form-group">
                <button type="submit" name="create_sub_'.$author.'" class="btn btn-primary">Subscribe To '. $author; echo ' <i class="fa fa-users" aria-hidden="true"></i></button>
            </div>
        </form>';
}

Answer 1

如果我说这种模式是个坏主意并且将User表和Subscription表

分开会更加可维护，那么它就无法回答这个问题

User只有用户（id，username ...）
Subscription会有subscriber和subscribed_to

因此，您可以轻松获取用户的订阅或订阅，而无需创建重复的信息

但也许你真的必须走这条路，所以不要接受这个建议，试试吧

所以你的问题可能来自if(isset($_POST['create_sub']))，这对每个用户都是如此（对于每个用户都是相同的验证）。

解决方案可以是：

将name="create_sub_'.$author.'"添加到您的提交按钮
选中isset($_POST["create_sub_{$author}"]而非if(isset($_POST['create_sub']))

编辑：必须使用isset($_POST["create_sub_{$author}"]的双引号将$ author用作php变量

使用表单循环遍历数组的麻烦

1 个答案: