Question

如何与地址联系？

  var uri = ContactsContract.Contacts.ContentUri;

        string[] projection = {
            ContactsContract.CommonDataKinds.StructuredPostal.InterfaceConsts.Id,
            ContactsContract.CommonDataKinds.StructuredPostal.InterfaceConsts.DisplayName,
            ContactsContract.CommonDataKinds.StructuredPostal.FormattedAddress
        };


        var cursor = Application.Context.ContentResolver.Query(uri, projection, null, null, null);

        var contactList = new List<(string id, string name, string address)>();

        if (cursor.MoveToFirst())
        {
            do
            {
                contactList.Add(
                    (
                        cursor.GetString(cursor.GetColumnIndex(projection[0])),
                        cursor.GetString(cursor.GetColumnIndex(projection[1])),
                        cursor.GetString(cursor.GetColumnIndex(projection[2]))
                    )
                );
            } while (cursor.MoveToNext());
        }

当我尝试这个时，我得到异常说“无效列数据1”我只想要联系人列表+他的地址

Answer 1

别名FormattedAddress（或data1）存在于以下提供商处：

content://com.android.contacts/data/phones

所以请使用ContactsContract.CommonDataKinds.Phone.ContentUri：

var uri = ContactsContract.CommonDataKinds.Phone.ContentUri;
string[] projection = {
    ContactsContract.CommonDataKinds.StructuredPostal.InterfaceConsts.Id,
    ContactsContract.CommonDataKinds.StructuredPostal.InterfaceConsts.DisplayName,
    ContactsContract.CommonDataKinds.StructuredPostal.FormattedAddress
};
var cursor = Application.Context.ContentResolver.Query(uri, projection, null, null, null);
var contactList = new List<(string id, string name, string address)>();
while (cursor.MoveToNext())
{
    contactList.Add(
        (
            cursor.GetString(cursor.GetColumnIndex(projection[0])),
            cursor.GetString(cursor.GetColumnIndex(projection[1])),
            cursor.GetString(cursor.GetColumnIndex(projection[2]))
        )
    );
}

Xamarin android获取地址联系人

1 个答案: