我一直试图在这里找到问题,但我似乎无法......我的onReceive似乎没有被召唤,这就是我所拥有的:<\ n / p>
public abstract class NoUpdatesTimer extends BroadcastReceiver {
private Context context;
private PendingIntent pendingIntent;
public NoUpdatesTimer(Context context) {
this.context = context;
Intent intent = new Intent(Constants.ALARM_NO_LOC_UPDATES);
pendingIntent = PendingIntent.getBroadcast(context, 0, intent, 0);
context.registerReceiver(this, new IntentFilter(Constants.ALARM_NO_LOC_UPDATES));
}
public void scheduleCheck(long delayMillis) {
AlarmManager alarmManager = (AlarmManager)context.getSystemService(Context.ALARM_SERVICE);
alarmManager.setExactAndAllowWhileIdle(AlarmManager.RTC_WAKEUP, System.currentTimeMillis() + delayMillis, pendingIntent);
}
@Override
public void onReceive(Context context, Intent intent) {
...
}
}
通过一些调试,我确认调用了scheduleChecking,但未调用onReceive方法。我还尝试使用以下命令从shell触发此代码:
adb shell am broadcast -a rsg.ms.7
(其中Constants.ALARM_NO_LOC_UPDATES是&#34; rsg.ms.7&#34;)。
你能告诉我要改变什么,以便调用onReceive吗?
答案 0 :(得分:0)
使用应用程序上下文而不是传入的服务上下文似乎使它工作,不确定原因:
public abstract class NoUpdatesTimer extends BroadcastReceiver {
private Context context;
private PendingIntent pendingIntent;
public NoUpdatesTimer(Context context) {
this.context = context.getApplicationContext();
Intent intent = new Intent(Constants.ALARM_NO_LOC_UPDATES);
pendingIntent = PendingIntent.getBroadcast(this.context, 0, intent, 0);
this.context.registerReceiver(this, new IntentFilter(Constants.ALARM_NO_LOC_UPDATES));
}
public void scheduleCheck(long delayMillis) {
AlarmManager alarmManager = (AlarmManager)this.context.getSystemService(Context.ALARM_SERVICE);
alarmManager.setExactAndAllowWhileIdle(AlarmManager.RTC_WAKEUP, System.currentTimeMillis() + delayMillis, pendingIntent);
}
@Override
public void onReceive(Context context, Intent intent) {
...
}
}
答案 1 :(得分:0)
SELECT productid, sum(count) as count, downloaddate FROM your_table GROUP BY downloaddate
的性质相对于#include <stdio.h>
typedef struct
{
int (*p)[2][2];
} S;
int main()
{
int aa[2][2] = {{1, 2}, {3, 4}};
S s = { .p = &aa };
printf("Four: %p\n", s.p[1][1]);
return 0;
}
绑定。
例如,它与Widgets的使用,其中广播在应用程序之外。
因此,当您在PendingIntent
中从ApplicationContext
广播时,您必须提供应用程序上下文而不是较低层。
我曾经遇到过同样的问题,花了我一整天的时间来解决这个问题。