我有以下数组,我希望能够删除所有" phonenumber"键,当然还有JSON对象的值。只有键" phonenumber"不是整个对象。我怎样才能做到这一点?
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答案 0 :(得分:4)
// make array
$array = json_decode($your_json_string, true);
// loop through array
foreach($array as $key => $item){
// unset them
unset($array[$key]["phonenumber"]);
}
// make json again
$json_string_modified = json_encode($array);
或使用参考
// make array
$array = json_decode($your_json_string, true);
// loop through array using reference
foreach($array as &$item){
// unset specific key
unset($item["phonenumber"]);
}
// unset reference
unset($item);
// make json again
// you may remove JSON_PRETTY_PRINT flag, I kept it just to see o/p
$json_string_modified = json_encode($array,JSON_PRETTY_PRINT);
答案 1 :(得分:1)
$jsonArray=json_decode($data);
//Remove unvanted props
foreach ($jsonArray as $key=>$row) {
foreach ($row as $prop=>$field) {
if ($prop != 'phonenumber')
$newArray[$key][$prop] = $field;
}
}
$jsonArray=json_encode($newArray);