将视图渲染为事件广播的响应

时间:2017-10-18 14:36:39

标签: laravel redis socket.io laravel-5.5

您好我正在开发一个使用事件broacasting troug redis和socket.io的Laravel webapp。一切正常,但我要将渲染的视图作为Event的响应返回。 Mi事件是这样的:

    <?php

namespace App\Events;

use Illuminate\Broadcasting\Channel;
use Illuminate\Queue\SerializesModels;
use Illuminate\Broadcasting\PrivateChannel;
use Illuminate\Broadcasting\PresenceChannel;
use Illuminate\Foundation\Events\Dispatchable;
use Illuminate\Broadcasting\InteractsWithSockets;
use Illuminate\Contracts\Broadcasting\ShouldBroadcast;

class EventName implements ShouldBroadcast
{
    use Dispatchable, InteractsWithSockets, SerializesModels;

    /**
     * Create a new event instance.
     *
     * @return void
     */

    public $data;

    public function __construct()
    {
        $this->data = array(
            'power'=> 'Funziona',
            'view'=> view('dashboard.partials.messages')->render()
        );
    }

    /**
     * Get the channels the event should broadcast on.
     *
     * @return \Illuminate\Broadcasting\Channel|array
     */
    public function broadcastOn()
    {
        return ['test-channel'];
    }
}

我使用此代码在页面上呈现响应:

<script src="/frontend/socket.io.js"></script>
    <script>
        var socket = io('http://1clickfashion.com:3002');
            socket.on("test-channel:App\\Events\\EventName", function(message){
            // increase the power everytime we load test route
            alert(message.data.power);
            $('#messages').html('');
            $('#messages').html(message.data.view);

        });
    </script>

“电源”警报正确显示,但视图也不起作用。在另一个视图中,我将视图用作return response()->json($view)并且完美地工作......有人有类似的问题吗?

1 个答案:

答案 0 :(得分:0)

对于在此问题上挣扎的任何人,通过将视图作为在Controller中呈现的变量传递来解决。像这样。

在控制器中:

$view = view('dashboard.partials.messages')->with('post', $post_c)->render();
        event(new \App\Events\Post($view));
事件中的

 public $data;

    public function __construct($view)
    {
        $this->data = array(
            'view'=> $view
        );
    }