我使用django-datable-view来渲染django模型中的数据。
在装饰网址之前一切正常,在我将login_required
添加到网址后,它引发了奇怪的错误。
根据该文档,它声明我可以将login_required
添加到网址。
以下是我的代码
from django_datatables_view.base_datatable_view import BaseDatatableView
class OrderListJson(BaseDatatableView):
# The model we're going to show
model = MyModel
# define the columns that will be returned
columns = ['number', 'user', 'state', 'created', 'modified']
# define column names that will be used in sorting
# order is important and should be same as order of columns
# displayed by datatables. For non sortable columns use empty
# value like ''
order_columns = ['number', 'user', 'state', '', '']
# set max limit of records returned, this is used to protect our site if someone tries to attack our site
# and make it return huge amount of data
max_display_length = 500
def render_column(self, row, column):
# We want to render user as a custom column
if column == 'user':
return '{0} {1}'.format(row.customer_firstname, row.customer_lastname)
else:
return super(OrderListJson, self).render_column(row, column)
def filter_queryset(self, qs):
# use parameters passed in GET request to filter queryset
# simple example:
search = self.request.GET.get(u'search[value]', None)
if search:
qs = qs.filter(name__istartswith=search)
# more advanced example using extra parameters
filter_customer = self.request.GET.get(u'customer', None)
if filter_customer:
customer_parts = filter_customer.split(' ')
qs_params = None
for part in customer_parts:
q = Q(customer_firstname__istartswith=part)|Q(customer_lastname__istartswith=part)
qs_params = qs_params | q if qs_params else q
qs = qs.filter(qs_params)
return qs
URL
url(_(r'^users/all/?$'),
login_required(dashboard.v1.views.OrderListJson.as_view()),
name='all_users'),
我一直收到错误500,如果我删除login_required,一切正常。如果我能得到关于如何装饰课堂观点的建议,我会很高兴,因为这是我想要实现的目标