我需要解析这个数据集,但我尝试了几种方法,但它不起作用。
{"id":2,"area_id":"1","payment_term_id":"1","payment_type_id":"1","trade_channel_id":"1","salesman_id":1,"customer_name":"xxx","contact_number":"1231212","fax_number":"1231232","home_address":"asd","delivery_address":"dasd","email_address":"test@edit.com","created_by":"4","updated_by":"4","is_active":"1","created_at":"2017-10-17 06:02:59","updated_at":"2017-10-17 06:13:22"}
我试过这个,但是这个错误说明了
(1/1)ErrorException 试图获得非对象的属性
$details = $request->get('details');
return $details->id;
我也试过这个
$details = $request->get('details');
return $details['id'];
(1/1)ErrorException 非法字符串偏移' id'
我正在使用laravel 5.4
答案 0 :(得分:1)
由于数据来自请求,因此它是JSON而不是集合或对象。所以,你需要做这样的事情:
return json_decode($request->details)->id;
答案 1 :(得分:1)
要在控制器中检索JSON有效内容,请使用:
$details = json_decode($request->details)->id);
dd($details);
而不是
$details = $request->get('details');
return $details['id'];
答案 2 :(得分:1)
要像$details['id']
一样使用数组,请尝试:
$details = json_decode($request->details, true);
echo $details['id'];