Question

我在我的应用程序中使用Retrofit从服务器下载一些JSON。但有时当我从服务器请求重复数据时，它返回带有空体的响应代码208，但是在200中我有一个非空的响应体。在null body中，改造转到onFailure方法。我的问题在这里！我想知道请求失败的原因（这是因为208（在我的情况下）或其他事情）。如何在OnFailure方法中获取响应代码？

我试图像这样实现我自己的callBack方法：

public class DefaultCallback<T> implements Callback<T> {

  private static final String TAG = "LOGO_SendReport";
  private Callback<T> callback;

  public DefaultCallback(Callback<T> callback) {
    this.callback = callback;
  }

  @Override
  public void onResponse(Call<T> call, Response<T> response) {
    if (response.body() == null) {

      callback.onFailure(call, new NullPointerException("Empty response"));
      Log.e(TAG, "Response code is: " + response.code());

    } else {
      callback.onResponse(call, response);
    }
  }

  @Override
  public void onFailure(Call<T> call, Throwable t) {
    Log.e(TAG, t.toString());
    callback.onFailure(call, t);
  }
}

这是我的电话：

 @POST("office/report")
  Call<ResponseSendReport> sendReport(@Body SendReport pendingList);

这是我的最终方法：

    final APIService service = ServiceGenerator.createService(APIService.class, App.Auth);

            Call<ResponseSendReport> call = service.sendReport(sendReport);

            call.enqueue(new Callback<ResponseSendReport>() {
              @Override
              public void onResponse(Call<ResponseSendReport> call, Response<ResponseSendReport> response) {

                Log.i("LOGO_SendReport", "code is:  " + response.code());


                if (response.code() == 200) {


              }

              @Override
              public void onFailure(Call<ResponseSendReport> call, Throwable t) {

                /*When Response code is 208 Goes here and I want to get 
                 response code 
                 if it is 208 to handle it! */
              }
            });

感谢您的帮助。

Answer 1

您可以创建抽象类并处理案例。

public abstract class DefaultCallback<T> implements Callback<T> {

   @SuppressWarnings({"ConstantConditions", "unchecked"})
   @Override public void onResponse(@NonNull Call<T> call, Response<T> response) {
       if (response.isSuccessful()) {
           onSuccess(response.body(), response.code());
       } else {
           onError(response.errorBody(), response.code());
       }
   }

   @Override public void onFailure(@NonNull Call<T> call, @NonNull Throwable throwable) {
       onError(null, -1);
   }

   public abstract void onSuccess(@NonNull final T response, int code);

   public abstract void onError(@Nullable ResponseBody body, int code);
}

Answer 2

您可以使用onResponse

在response.code()方法中获取回复代码

@Override
public void onResponse(Call<ResponseSendReport> call, Response<ResponseSendReport> response) {
    if (response.isSuccessful()) {
        if (response.code() == 208) {
           //do sth
        } else {
           //do sth
        }
    } else {
        //do sth
    }
}

Answer 3

1.您只需修改通话：

 @POST("office/report")
 Call<Response<ResponseSendReport>> sendReport(@Body SendReport pendingList);

2.这是你最后的方法：

 @Override
 public void onFailure(Call<Response<ResponseSendReport>> response, Throwable t) {

    response.code() //  /** HTTP status code. */
    response.body() //your object
          }
        });

如何通过改造创建新的CallBack

3 个答案: