我正在重新列出李的相关文章列表,我想删除" - "标签和跨度之间没有弄乱页面上的原始内容(链接)。我必须使用jQuery,我不确定是否有一种简单的方法可以做到这一点。
<div class="related-articles card">
<h3 class="h2">
<i class="fa fa-book text-brand-primary-dark"></i> Related Articles
</h3>
<ul>
<li>
<a href="http://example.com/article-1">Title One</a>
-
<span> Some Related Preview Text... </span>
</li>
<li>
<a href="http://example.com/article-2">Title Two</a>
-
<span> Some Related Preview Text... </span>
</li>
<li>
<a href="http://example.com/article-3">Title Three</a>
-
<span> Some RelatedPreview Text... </span>
</li>
</ul>
答案 0 :(得分:1)
这是我的解决方案,获取子元素并将其分配回来,因此显示的纯文本(-
)将被删除!
$('.related-articles li').each(function() {
$(this).html($(this).children());
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="related-articles card">
<h3 class="h2">
<i class="fa fa-book text-brand-primary-dark"></i> Related Articles
</h3>
<ul>
<li>
<a href="http://example.com/article-1">Title One</a> -
<span> Some Related Preview Text... </span>
</li>
<li>
<a href="http://example.com/article-2">Title Two</a> -
<span> Some Related Preview Text... </span>
</li>
<li>
<a href="http://example.com/article-3">Title Three</a> -
<span> Some RelatedPreview Text... </span>
</li>
</ul>
答案 1 :(得分:1)
一种方法是遍历每个<li>
,提取<a>
和<span>
元素并手动将它们拼接在一起,如下所示:
$("ul > li").each( (i, li) => {
const $li = $(li);
const $a = $li.find("a");
const $span = $li.find("span");
//create a temp element with just the <a> and <span>
const $tempItem = $("<li></li>");
$tempItem.append( $a ).append( $span );
//copy new HTML into old element
$li.html( $tempItem.html () );
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
<li>
<a href="http://example.com/article-1">Title One</a>
-
<span> Some Related Preview Text... </span>
</li>
<li>
<a href="http://example.com/article-2">Title Two</a>
-
<span> Some Related Preview Text... </span>
</li>
<li>
<a href="http://example.com/article-3">Title Three</a>
-
<span> Some RelatedPreview Text... </span>
</li>
</ul>
&#13;
答案 2 :(得分:0)
一个选项是:
$('.related-articles li a').map(function() {
return this.nextSibling;
}).remove();