我在一个网页上显示SQL数据,该网页用于显示不同列数的不同表格。对于具有空值的表,我不希望这些表显示在HTML表上。如何创建它以便它们不显示?
String userAgent = Util.getUserAgent(this, "Bakingapp");
MediaSource mediaSource = new ExtractorMediaSource(uri, defaultDataSourceFactory,new
DefaultExtractorsFactory(), null, null);
mExoPlayer.prepare(mediaSource);
mExoPlayer.setPlayWhenReady(true);
我也试过了:
<?php
$sql1 = "SELECT * FROM lists WHERE id = $listid";
$result1 = $mysqli->query($sql1);
while ($row = $result1->fetch_assoc()) {
$id = $row['id'];
$name = $row['name'];
$list_id = $row['list_id'];
$description = $row['description'];
$status = $row['status'];
$col1_name = $row['col1_name'];
$col2_name = $row['col2_name'];
$col3_name = $row['col3_name'];
$col4_name = $row['col4_name'];
$col5_name = $row['col5_name'];
$col6_name = $row['col6_name'];
$col7_name = $row['col7_name'];
$col8_name = $row['col8_name'];
$col9_name = $row['col9_name'];
$col10_name = $row['col10_name'];
$col11_name = $row['col11_name'];
$col12_name = $row['col12_name'];
$col13_name = $row['col13_name'];
$col14_name = $row['col14_name'];
$col15_name = $row['col15_name'];
}
// $id = $_GET["id"];
$sql = "SELECT * FROM list_rows WHERE list_id = $listid";
$result = $mysqli->query($sql);
if ($result->num_rows) {
echo "<table class='w3-table-all' id='datatable'>
<thead>
<tr class='w3-indigo'>";
if (!empty($row['col1_name'])){echo "<th>".$col1_name."</th>";}
if (!empty($row['col2_name'])){echo "<th>".$col2_name."</th>";}
if (!empty($row['col3_name'])){echo "<th>".$col3_name."</th>";}
if (!empty($row['col4_name'])){echo "<th>".$col4_name."</th>";}
if (!empty($row['col5_name'])){echo "<th>".$col5_name."</th>";}
if (!empty($row['col6_name'])){echo "<th>".$col6_name."</th>";}
if (!empty($row['col7_name'])){echo "<th>".$col7_name."</th>";}
if (!empty($row['col8_name'])){echo "<th>".$col8_name."</th>";}
if (!empty($row['col9_name'])){echo "<th>".$col9_name."</th>";}
if (!empty($row['col10_name'])){echo "<th>".$col10_name."</th>";}
if (!empty($row['col11_name'])){echo "<th>".$col11_name."</th>";}
if (!empty($row['col12_name'])){echo "<th>".$col12_name."</th>";}
if (!empty($row['col13_name'])){echo "<th>".$col13_name."</th>";}
if (!empty($row['col14_name'])){echo "<th>".$col14_name."</th>";}
if (!empty($row['col15_name'])){echo "<th>".$col15_name."</th>";}
echo "</tr>
</thead>";
// output data of each row
echo "<tbody>";
while($row = $result->fetch_assoc()) {
echo "
<tr class='w3-hover-pale-blue'>";
if (!empty($row["col1_value"])){echo "<th>".$col1_value."</th>";}
if (!empty($row["col2_value"])){echo "<th>".$col2_value."</th>";}
if (!empty($row["col3_value"])){echo "<th>".$col3_value."</th>";}
if (!empty($row["col4_value"])){echo "<th>".$col4_value."</th>";}
if (!empty($row["col5_value"])){echo "<th>".$col5_value."</th>";}
if (!empty($row["col6_value"])){echo "<th>".$col6_value."</th>";}
if (!empty($row["col7_value"])){echo "<th>".$col7_value."</th>";}
if (!empty($row["col8_value"])){echo "<th>".$col8_value."</th>";}
if (!empty($row["col9_value"])){echo "<th>".$col9_value."</th>";}
if (!empty($row["col10_value"])){echo "<th>".$col10_value."</th>";}
if (!empty($row["col11_value"])){echo "<th>".$col11_value."</th>";}
if (!empty($row["col12_value"])){echo "<th>".$col12_value."</th>";}
if (!empty($row["col13_value"])){echo "<th>".$col13_value."</th>";}
if (!empty($row["col14_value"])){echo "<th>".$col14_value."</th>";}
if (!empty($row["col15_value"])){echo "<th>".$col15_value."</th>";}
echo "</tr>";
}
echo "</tbody>";
echo "</table>";
} else {
echo "0 results";
}
echo "</div>";
//$mysqli->close();
?>
和is_null,以及:
if (!is_null($row['col1_name'])){echo "<th>".$col1_name."</th>";}
这些变化都没有奏效。它要么显示空表,要么根本不显示任何内容。
if ($row['col1_name'] != null){echo "<th>".$col1_name."</th>";}
数据库数据
答案 0 :(得分:0)
根据此StackOverflow帖子(PHP: using empty() for empty string?),您不应使用empty
来确定字符串长度,因为变量本身就存在。鉴于出现一些复杂的情况,empty
最适合用于数组。
根据empty
的{{3}},以下情况会评估为empty
返回TRUE。
以下内容被认为是空的:
因此,我会比较一个空字符串:
if ($row['col1_name'] == ''){echo "<th>".$col1_name."</th>";}