Question

我正在审核this question并发现了一些我不理解的内容。

将此文件夹与一个msi文件和一个txt文件一起考虑。为什么Test-Path对msi文件返回false？我期望两个测试路径cmdlet都为$ True，因为这些文件位于文件夹中。

$fldr = 'C:\AMD\WU-CCC2\ccc2_install\CN\amddvr\amddvr64'
$file = 'eval.msi'
$fullPath = Join-Path -Path $fldr -ChildPath $file

Write-Host '   Testing Path to ' $fullPath

Set-Location -Path $fldr
    Test-Path  -LiteralPath $fullPath


set-location -Path c:\
    Test-Path  -LiteralPath $fullPath 


$file = 'me.txt'
$fullPath = Join-Path -Path $fldr -ChildPath $file

Write-Host '   Testing Path to ' $fullPath

Set-Location -Path $fldr
    Test-Path  -LiteralPath $fullPath

set-location -Path c:\
    Test-Path  -LiteralPath $fullPath

这是输出

   Testing Path to  C:\AMD\WU-CCC2\ccc2_install\CN\amddvr\amddvr64\eval.msi
False
False
   Testing Path to  C:\AMD\WU-CCC2\ccc2_install\CN\amddvr\amddvr64\me.txt
True
True

如评论所述：

ls $fldr
ls $fldr | % { '-{0}-' -f $_.name }

返回以下内容：

Directory: C:\AMD\WU-CCC2\ccc2_install\CN\amddvr\amddvr64


Mode                LastWriteTime         Length Name                                                                                                                              
----                -------------         ------ ----                                                                                                                              
-a----        9/27/2017   3:03 PM        8945664 amddvr64.msi                                                                                                                      
-a----       10/17/2017   6:21 AM              6 me.txt

和

   -amddvr64.msi-
   -me.txt-

Test-Path和msi文件

0 个答案: