Question

表具有以下结构：groupTable＆gt; lineGroupJoinTable＆gt; linesTable（名称是混淆的名称）我有以下查询返回此错误：

子查询返回的值超过1。这是不允许的子查询跟随=，！=，＆lt;，＆lt; =，＆gt;，＆gt; =或当子查询用作表达。

问题是我希望由于子查询是组，我不应该得到这个错误。我可能错过了一些东西。

UPDATE dbo.groupTable
SET fieldToUpdate = CASE WHEN fieldToUpdate IS NULL THEN NULL ELSE
(
    SELECT  sumTable.fieldToSum FROM
    dbo.groupTable gt
    INNER JOIN
    (
        SELECT lgjt.groupdId1, lgjt.groupdId2, SUM(lt.fieldToSum) as fieldToSum
        FROM lineGroupJoinTable lgjt
        INNER JOIN linesTable lt
            ON
                lt.fieldToSum IS NOT NULL AND lt.fieldToSum > 0 AND
                lgjt.lineId1 = lt.lineId1 AND lgjt.lineId2 = lt.lineId2
        GROUP BY lgjt.groupdId1, lgjt.groupdId2

    ) sumTable
    ON sumTable.groupdId1 = gt.groupdId1 AND sumTable.groupdId2 = gt.groupdId2
)
END

此变体也尝试遵循建议但返回相同的错误：

UPDATE dbo.groupTable
SET fieldToUpdate = CASE WHEN fieldToUpdate IS NULL THEN NULL ELSE
(
    SELECT  SUM(sumTable.fieldToSum) FROM
    dbo.groupTable gt
    INNER JOIN
    (
        SELECT lgjt.groupdId1, lgjt.groupdId2, SUM(lt.fieldToSum) as fieldToSum
        FROM lineGroupJoinTable lgjt
        INNER JOIN linesTable lt
            ON
                lt.fieldToSum IS NOT NULL AND lt.fieldToSum > 0 AND
                lgjt.lineId1 = lt.lineId1 AND lgjt.lineId2 = lt.lineId2
        GROUP BY lgjt.groupdId1, lgjt.groupdId2

    ) sumTable
    ON sumTable.groupdId1 = gt.groupdId1 AND sumTable.groupdId2 = gt.groupdId2
    GROUP BY gt.groupdId1, gt.groupdId2
)
END

Answer 1

可能是因为dbo.groupTable具有组合id1和id2的多个值。我建议将id1和id2列分组并进行SUM，这种情况下你只有1个结果。

UPDATE dbo.groupTable
SET fieldToUpdate = CASE WHEN fieldToUpdate IS NULL THEN NULL ELSE
(
    SELECT  SUM(sumTable.fieldToSum) FROM
    dbo.groupTable gt
    INNER JOIN
    (
        SELECT lgjt.id1, lgjt.id2, SUM(lt.fieldToSum) as fieldToSum
        FROM lineGroupJoinTable lgjt
        INNER JOIN linesTable lt
            ON
                lt.fieldToSum IS NOT NULL AND lt.fieldToSum > 0 AND
                lgjt.id3 = lt.id3 AND lgjt.id4 = lt.id4
        GROUP BY lgjt.id1, lgjt.id2
    ) sumTable
    ON  sumTable.id1 = gt.id1 AND sumTable.id2 = gt.id2
    GROUP BY gt.id1, gt.id2
)
END

意外的“子查询返回超过1个值”

1 个答案: