我想预先填写我的html表单字段"参考"来自引用的url值是否为ref?= 1234如何使用laravel
<form method="post" accept-charset="utf-8" class="block" enctype="multipart/form-data" action="{{ route('register') }}">
{!! csrf_field() !!}
<div class="row">
<div class="col-md-12 col-sm-12">
<div style="width: 100%" class="alert alert-warning">
Please Register With a Reference User.
</div>
</div>
</div>
<div class="input-group">
<input type="text" name="reference" value="HERE WANT TO SHOW REFEERENCE CODE FROM URL" required class="form-control" placeholder="Enter Reference ID *" aria-describedby="basic-addon1">
<span class="input-group-addon" id="basic-addon1"><i class="fa fa-handshake-o"></i></span>
</div>
答案 0 :(得分:2)
您可以使用:
<input type="text" name="reference" value="{{ app('request')->input('ref') }}" required class="form-control" placeholder="Enter Reference ID *" aria-describedby="basic-addon1">
答案 1 :(得分:1)
试试这个。输入(&#39; ref&#39;)}}&#34;要求的等级=&#34;形式控制&#34;占位符=&#34;输入参考ID *&#34;咏叹调-describedby =&#34;碱性addon1&#34;&GT;
答案 2 :(得分:0)
PHP中没有$GET
变量。
有$_GET。
在laravel中,您可以使用Request外观或Input外观
所以这里:
<input value="view{{ \Request::get('ref') }}" type="text" name="reference" required class="form-control" placeholder="Enter Reference ID *" aria-describedby="basic-addon1">
// http://localhost/codec/register?ref=g5M089zQeVzc
// will produce
// <input value="viewg5M089zQeVzc" ...
答案 3 :(得分:0)
使用request()
帮助:
$ref = request('ref'); // It will return 1234.