Question

我想在某些情况下分配一些值，请帮助我，我现有的代码是

while($local_data = mysqli_fetch_assoc($query) ){
    $category = explode('->',$local_data['breadcrumbs']);
    echo $category[2]; echo "<br />";
    if(strtolower(trim($category[2])) =='outdoor'){
        $cat_ID = 5;
    }
    if(strtolower(trim($category[2]))=='furniture'){
        $cat_ID = 20;
    }

    if(strtolower(trim($category[2]))=='Bathroom'){
        $cat_ID = 6;
    }
    if(strtolower(trim($category[2]))=='Furniture'){
        $cat_ID = 15;
    }
    if(strtolower(trim($category[2]))=='Office'){
        $cat_ID = 62;
    }
    if(strtolower(trim($category[2]))=='Contract'){
        $cat_ID = 81;
    }
    if(strtolower(trim($category[2]))=='Decor'){
        $cat_ID = 90;
    }
    if(strtolower(trim($category[2]))=='Construction'){
        $cat_ID = 108;
    }
    if(strtolower(trim($category[2]))=='Tech'){
        $cat_ID = 133;
    }

    echo $cat_ID; echo "<br />";

} 现在它不会进入if条件

我已经编辑了代码，

Answer 1

您最好在数组中创建类别的“地图”，而不是编写大量if's。这样，如果要测试是否找到类别，您只需要一个

<?php
      $categories = [
            'outdoor'         => 5,
            'furniture'       => 20,
            'bathroom'        => 6,
            'furniture'       => 15,
            'office'          => 62,
            'contract'        => 81,
            'decor'           => 90,
            'construction'    => 108,
            'tech'            => 133,
      ];

      while($local_data = mysqli_fetch_assoc($query)){
          $category = explode('->',$local_data['breadcrumbs']);
          $category_id = isset($categories[trim(strtolower($category[2]))]) ? $categories[trim(strtolower($category[2]))] : null;
          echo 'Category ID = '. ($category_id ?: 'Not found');
      }

Answer 2

您需要放置以下条件

if(strtolower(trim($category[2])) =='outdoor'){
    $cat_ID = 5;
    exit(); 
}

我的if条件不工作php

2 个答案: