有人提出类似的问题,所以我道歉,但没有一个人能够帮助我。
我正在努力通过完成处理程序将此异步请求中的值返回到Firebase。我从Firebase检索的值是一个数组,它确实存在。但是
以下是我向Firebase发出请求的功能:
class SearchManager {
var searchResults = [String]()
var listOfMosaics = [String]()
// Retrieves company list from Firebase
func getMosaicTitles(completionHandler: @escaping (_ mosaics: [String]) -> ()) {
Database.database().reference().child("mosaics").observeSingleEvent(of: .value, with: { (snapshot) in
guard let allMosaics = snapshot.value as? [String] else {
print("unable to unwrapp datasnapshot")
return
}
completionHandler(allMosaics)
})
}
// resets search results array
func resetSearch() {
searchResults = []
}
// takes list of all mosaics and filters based on search text
func filterAllMosaics(searchText: String) {
searchResults = listOfMosaics.filter { $0.contains(searchText) }
}
}
在AppDelegate中,我称之为发布通知:
let searchManager = SearchManager()
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
makeRootViewLaunchScreen()
FirebaseApp.configure()
searchManager.getMosaicTitles { (results) in
self.searchManager.listOfMosaics = results
NotificationCenter.default.post(name: NSNotification.Name("mosaicsReturned"), object: nil)
self.stopDisplayingLaunchScreen()
}
// Adds border to bottom of the nav bar
UINavigationBar.appearance().shadowImage = UIImage.imageWithColor(color: UIColor(red:0.00, green:0.87, blue:0.39, alpha:1.0))
// Override point for customization after application launch.
return true
}
func makeRootViewLaunchScreen() {
let mainStoryboard: UIStoryboard = UIStoryboard(name: "LaunchScreen", bundle: nil)
let viewController = mainStoryboard.instantiateViewController(withIdentifier: "launchScreen")
UIApplication.shared.keyWindow?.rootViewController = viewController
}
// reassigns root view after Firebase request complete
func stopDisplayingLaunchScreen() {
let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
let viewController = mainStoryboard.instantiateViewController(withIdentifier: "centralViewController")
UIApplication.shared.keyWindow?.rootViewController = viewController
}
在viewController的viewDidLoad中,它支持使用检索到的数组填充它的tableView,我添加了一个Notification Observer。
var listOfMosaics = [String]()
var searchResults = [String]() {
didSet {
tableView.reloadData()
}
}
override func viewDidLoad() {
super.viewDidLoad()
listOfMosaics = searchManager.listOfMosaics
configureSearchBar()
configureSearchBarTextField()
self.tableView.separatorColor = UIColor(red:0.00, green:0.87, blue:0.39, alpha:1.0)
NotificationCenter.default.addObserver(self, selector: #selector(updateListOfMosaics), name: NSNotification.Name("mosaicsReturned"), object: nil)
}
@objc func updateListOfMosaics(notification: Notification) {
listOfMosaics = searchManager.listOfMosaics
}
但是当我调用下面的代码时,它不起作用,数组打印为空,因此它不会更新我的tableView。
extension SearchResultsTableViewController: UISearchBarDelegate {
func searchBarSearchButtonClicked(_ searchBar: UISearchBar) {
searchManager.resetSearch()
searchManager.filterAllMosaics(searchText: searchBar.text!)
tableView.reloadData()
print(listOfMosaics)
print(searchResults)
}
}
先谢谢你的帮助。
答案 0 :(得分:1)
这应该适合你。我认为你没有将SearchManager的实例从你的AppDelegate传递给你的ViewController。我猜你在ViewController中创建了一个新的SearchManager实例,它有一个空数组。
搜索管理器:
class SearchManager {
var searchResults = [String]()
var listOfMosaics = [String]()
func getMosaicTitles(completionHandler: @escaping (_ mosaics: [String]) -> ()) {
Database.database().reference().child("mosaics").observeSingleEvent(of: .value, with: { (snapshot) in
guard let allMosaics = snapshot.value as? [String] else {
print("unable to unwrapp datasnapshot")
completionHandler([]) // <- You should include this too.
return
}
completionHandler(allMosaics)
})
}
func resetSearch() {
searchResults = []
}
func filterAllMosaics(searchText: String) {
searchResults = listOfMosaics.filter { $0.contains(searchText) }
}
}
查看控制器:
class TableViewController: UITableViewController {
var searchManager: SearchManager?
var listOfMosaics = [String]()
var searchResults = [String]() {
didSet {
tableView.reloadData()
}
}
override func viewDidLoad() {
super.viewDidLoad()
guard let searchManager = searchManager else { return }
listOfMosaics = searchManager.listOfMosaics
print("List of mosaics: \(listOfMosaics)")
}
override func numberOfSections(in tableView: UITableView) -> Int {
return 0
}
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return 0
}
}
<强>的AppDelegate:强>
class AppDelegate: UIResponder, UIApplicationDelegate {
var window: UIWindow?
let searchManager = SearchManager()
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
makeRootViewLaunchScreen()
FirebaseApp.configure()
searchManager.getMosaicTitles { results in
self.searchManager.listOfMosaics = results
self.stopDisplayingLaunchScreen()
}
return true
}
func makeRootViewLaunchScreen() {
let mainStoryboard: UIStoryboard = UIStoryboard(name: "LaunchScreen", bundle: nil)
let viewController = mainStoryboard.instantiateViewController(withIdentifier: "launchScreen")
window?.rootViewController = viewController
window?.makeKeyAndVisible()
}
func stopDisplayingLaunchScreen() {
let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
guard let viewController = mainStoryboard.instantiateViewController(withIdentifier: "centralViewController") as? TableViewController else { return }
let navigationController = UINavigationController(rootViewController: viewController)
viewController.searchManager = searchManager
window?.rootViewController = navigationController
window?.makeKeyAndVisible()
}
}
答案 1 :(得分:0)
正如@TNguyen在评论中所说,听起来你并没有等待异步函数getMosaicTitles()
完成。
您可能希望在呼叫运行时禁用搜索栏按钮,并在呼叫完成后从完成处理程序启用它。然后,在结果加载完毕之前,用户将无法单击搜索按钮。
答案 2 :(得分:0)
您可以在后台线程中从数据库中获取数据并添加完成块,以便tableView仅在获取更新的内容后重新加载。