您可以在Python中创建变量列表而无需实例化变量吗?

时间:2017-10-16 13:21:14

标签: python list loops variables

我试图让我的代码更清洁。

我想做类似的事情:

gesture_sensor_data = [nod_gyro, nod_acc, swipe_left_gyro, swipe_right_acc, etc.]

我现在有这个:

nod_gyro, nod_acc = fill_gyro_and_acc_data(nod_intervals, merge)
swipe_right_gyro, swipe_right_acc = fill_gyro_and_acc_data(swipe_right_intervals, merge)
swipe_left_gyro, swipe_left_acc = fill_gyro_and_acc_data(swipe_left_intervals, merge)
whats_up_gyro, whats_up_acc = fill_gyro_and_acc_data(whats_up_intervals, merge)

我想在gesture_sensor_data中运行循环。

有办法做到这一点吗?某种结构还是什么?

编辑:我只是在这个函数中显示我的完整代码以获取上下文。

def generate_gesture_files(i):
    nod_intervals, swipe_left_intervals, swipe_right_intervals, whats_up_intervals = generate_gesture_intervals(i)

    merge = pandas.read_csv(final_user_study_path + "/P" + str(i) + "/DataCollection/data/merge.csv")
    nod_gyro, nod_acc = fill_gyro_and_acc_data(nod_intervals, merge)
    swipe_right_gyro, swipe_right_acc = fill_gyro_and_acc_data(swipe_right_intervals, merge)
    swipe_left_gyro, swipe_left_acc = fill_gyro_and_acc_data(swipe_left_intervals, merge)
    whats_up_gyro, whats_up_acc = fill_gyro_and_acc_data(whats_up_intervals, merge)
    return nod_gyro, nod_acc, swipe_right_gyro, swipe_right_acc, swipe_left_gyro, swipe_right_acc, whats_up_gyro, whats_up_acc

2 个答案:

答案 0 :(得分:1)

itertools.chain([fill_gyro_and_acc_data(i, merge) for i in [
    nod_intervals, swipe_right_intervals, swipe_left_intervals, whats_up_intervals
])

答案 1 :(得分:0)

您可以更改generate_gesture_intervals并使用部分

def generate_gesture_files(i):
  return reduce(lambda x,y:x+y, [fill_gyro_and_acc_data(arg, merge) for arg in generate_gesture_intervals(i)])