Question

我正在开发一个需要pdf / doc文件上传的简单软件学院项目。但是这里出现了瓶颈：我无法使用Sequelize ORM在任何地方找到这个功能的示例和示例。

有没有人使用这个框架做过类似的事情？

*顺便说一句，我知道express（）有几个npm包，但我必须使用sequelize。

欢迎任何建议。

提前致谢;）

Answer 1

使用multer配置您的快速应用。阅读multer的文档，但简而言之，您可以存储上传文件的路径：

const multer = require('multer')
const express = require('express')
const Sequelize = require('sequelize')
const sequelize = new Sequelize('database', 'username', 'password')

const MyModel = sequelize.define('myModel', {
  filePath: Sequelize.STRING,
})

const express = express()

const storage = multer.diskStorage({
  destination: (req, file, cb) => {
    cb(null, './app/uploads')
  },
  filename: (req, file, cb) => {
    cb(null, file.originalname)
  }
})

app.post('/upload', multer({ storage }).single('example), async (req, res) => {
    // This needs to be done elsewhere. For this example we do it here.
    await sequelize.sync()

    const filePath = `${req.file.destination}/${req.file.filename}`

    const myModel = await MyModel.create({ filePath })
})

Answer 2

使用AJAX的一个稍微简单的示例（from）。

添加到您的node.js

var multer = require('multer');

const storage = multer.diskStorage({
    destination: (req, file, callback) => {
        console.log(req);
        callback(null, './uploads');
    },
    filename: (req, file, callback) => {
        console.log(req);
        callback(null, Date.now() + file.originalname);
    }
});

var upload = multer({storage:storage}).single('myFile');

app.post('/dashboard/myFile', function(req,res){
        upload(req,res,function(err){
            //console.log("owen",req.file,err);
            if (err)
                return res.end("error uploading file");
            res.end("file is uploaded");
        });
});

并在您的HTML中

<form id="myForm" name="myForm" enctype="multipart/form-data" method="post">
    <input id="myFile" name="myFile" type="file">
    <button type="submit" class="btn btn-primary">Submit</button>
</form>


<script>

var form = document.forms.namedItem("myForm");

form.addEventListener('submit', function(ev){
    var myFile = document.getElementById('myFile').files[0];
    var oData = new FormData(form);
    var oReq = new XMLHttpRequest();
    oReq.open("POST","/uploadFile",true);
    oReq.onload = function(oEvent){
        if(oReq.status == 200) {
            console.log("success",oEvent);
        } else {
            console.log("fail",oEvent);
        }
    }
    oReq.send(oData);
    ev.preventDefault();
},false);

</script>

如何使用sequelize + mysql + express js处理文件上传？

2 个答案: