Question

我正在尝试创建一个队列列表，并且我正在传递链接列表的引用，但它无法正常工作并给出错误。

在函数＆＃39; void insertDataToQueue（Node **，int）＆＃39;：请求会员＆＃39; next＆＃39;在＆＃39; * temp＆＃39;中，它是指针类型＆＃39; Node * {aka node *}＆＃39; （也许你打算使用＆＃39; - ＆gt;＆＃39;？）|

 void insertDataToQueue(Node **queueList, int burstTime){
    Node *newNode = new Node;
    newNode->burstTime = burstTime;
    newNode->next = NULL;

if(queueList == NULL){
    *queueList = newNode;
}
else{
    Node **temp = queueList;
    while(*temp != NULL)
        temp = *temp->next;
}
}

Answer 1

要迭代整个列表，只需一个指向public class ChatHeadFrameLayout extends FrameLayout { /** * Store the initial touch down x coordinate */ private float initialTouchX; /** * Store the initial touch down y coordinate */ private float initialTouchY; public ChatHeadFrameLayout(@NonNull Context context) { super(context); } public ChatHeadFrameLayout(@NonNull Context context, @Nullable AttributeSet attrs) { super(context, attrs); } public ChatHeadFrameLayout(@NonNull Context context, @Nullable AttributeSet attrs, @AttrRes int defStyleAttr) { super(context, attrs, defStyleAttr); } @RequiresApi(21) public ChatHeadFrameLayout(@NonNull Context context, @Nullable AttributeSet attrs, @AttrRes int defStyleAttr, @StyleRes int defStyleRes) { super(context, attrs, defStyleAttr, defStyleRes); } @Override public boolean onInterceptTouchEvent(MotionEvent event) { // If the event is a move, the ViewGroup needs to handle it and return // the indication here switch (event.getAction()) { case MotionEvent.ACTION_DOWN: //remember the initial position initialTouchX = event.getRawX(); initialTouchY = event.getRawY(); return true; } return false; } @Override public boolean onTouchEvent(MotionEvent event) { // Will be called in case we decide to intercept the event // Handle the view move-with-touch behavior here switch (event.getAction()) { case MotionEvent.ACTION_DOWN: //remember the initial position initialTouchX = event.getRawX(); initialTouchY = event.getRawY(); return true; case MotionEvent.ACTION_UP: int Xdiff = (int) (event.getRawX() - initialTouchX); int Ydiff = (int) (event.getRawY() - initialTouchY); //The check for Xdiff <10 && YDiff< 10 because sometime elements moves a little while clicking. //So that is click event. if (Xdiff < 10 && Ydiff < 10) { return false; } return true; case MotionEvent.ACTION_MOVE: //Calculate the X and Y coordinates of the view. setX(event.getRawX() - initialTouchX); setY(event.getRawY() - initialTouchY); //Update the layout with new X & Y coordinate invalidate(); return true; } return false; } }的简单指针即可：

Node

现在，没有任何链接，我想（我希望）仅用于学习方面。因为C ++就像你需要的每个容器一样。例如，您有void insertDataToQueue(Node **queueList, int burstTime){ Node *newNode = new Node; newNode->burstTime = burstTime; newNode->next = NULL; if(queueList == NULL) { *queueList = newNode; } else { Node *temp = *queueList; // Find last element, ie element who "next" field is NULL while(temp->next != NULL) { temp = temp->next; } // Make last element to point to new element temp->next = newNode; } }或std::list链接列表。对于生产代码，更喜欢使用它而不是自己开发。

Answer 2

这个

*temp->next;

被解析为

*(temp->next);

因为-> has higher precedence than *，如果你想首先取消引用然后访问该成员，你可以使用括号：

(*temp)->next;

使用引用无效的遍历链接列表

2 个答案: