从列表中的值向列表中的dicts添加键

时间:2017-10-16 11:28:43

标签: python list loops dictionary key

如果dict包含某个键,如何从另一个列表中的值中添加键到列表中的dict?

我有一个dicts列表。这些dicts只包含一个键('review')或两个键('review'和'response')。当dict包含键'response'时,我想添加两个键,其中包含两个列表中的值。

data = [{'response': 'This is a response',
         'review': 'This is a review'},
        {'review': 'This is only a review'},
        {'response': 'This is also a response',
         'review': 'This is also a review'}]
date = ['4 days ago',
        '3 days ago']
responder = ['Manager',
             'Customer service']

我已尝试过以下内容,但由于每个包含密钥“响应”的dict我只想从每个列表的值中添加1,我不知道如何执行此操作。

for d in data:
    if 'response' in d:
        for i in date:
            d['date'] = i
        for i in responder:
            d['responder'] = i

输出显示我当然只添加列表的最后一个值,因为我循环遍历列表。我该如何解决这个问题?

[{'date': '3 days ago',
  'responder': 'Customer service',
  'response': 'This is a response',
  'review': 'This is a review'},
 {'review': 'This is only a review'},
 {'date': '3 days ago',
  'responder': 'Customer service',
  'response': 'This is also a response',
  'review': 'This is also a review'}]

3 个答案:

答案 0 :(得分:4)

您可以为日期和响应者列表创建一个迭代器,然后在if语句中调用next()以从列表中获取下一个项目

data = [{'response': 'This is a response', 
         'review': 'This is a review'}, 

        {'review': 'This is only a review'}, 

        {'response': 'This is also a response', 
         'review': 'This is also a review'}]

date = ['4 days ago', '3 days ago']
responder = ['Manager', 'Customer service']

d_iter = iter(date)
r_iter = iter(responder)

for d in data:
    if 'response' in d:
        d['date'] = next(d_iter)
        d['responder'] = next(r_iter)

print(data)
>> [
{'date': '4 days ago', 
 'review': 'This is a review', 
 'responder': 'Manager', 
 'response': 'This is a response'},  

{'review': 'This is only a review'}, 

{'date': '3 days ago', 
 'review': 'This is also a review', 
 'responder': 'Customer service', 
 'response': 'This is also a response'}
]

答案 1 :(得分:2)

你可以试试这个,但要小心,因为你名单上response的数量应该等于列表的长度:

d_r = zip(date, responder)

for d in data:
    if 'response' in d:
            d['date'], d['responder'] = next(d_r)
print(data)

答案 2 :(得分:0)

我认为您正在尝试添加两个条目,其中Date为键,值不同。在字典中你不能有重复的键。这就是为什么在for循环字典只更新了一个日期键条目和只有一个响应者条目

之后