使用最大字符的最后一个空格拆分字符串

时间:2017-10-16 10:26:24

标签: java string split

我正在尝试将具有最大允许字符的Last空格的String拆分:

期望:

String name =" John David Guetta MarkHenry Anthoney Sam";

允许的最大字符数: 30

所以它应该返回:

John David Guetta MarkHenry 
Anthoney Sam

实际结果:

 John David Guetta MarkHenry An
 thoney Sam

代码:

 public static List<String> splitByLength(String str, int n) {
    List<String> returnList = new ArrayList<>();
    StringBuilder sb = new StringBuilder();

    for (int i = 0; i < str.length(); i++) {
        if (i > 0 && (i % n == 0)) {
            returnList.add(sb.toString());
            sb = new StringBuilder();
        }

        sb.append(str.charAt(i));
    }
    if (StringUtils.isNoneBlank(sb.toString())) {
        returnList.add(sb.toString());
    }
    return returnList;
}

2 个答案:

答案 0 :(得分:0)

您可以使用最多可接受30个字符的正则表达式:

String name = "John David Guetta MarkHenry Anthoney Sam";
Pattern p = Pattern.compile(".{1,30}(\\s+|$)");
Matcher m = p.matcher(name);
while(m.find()) {
  System.out.println(m.group().trim());
}

注意(\\s|$)要么在空格上打破要么在初始字符串结束时打破。

答案 1 :(得分:0)

我总是发现使用正则表达式很困难和麻烦,所以这里有一个我会用的解决方案

 private static void splitByLength(String str, int n) {
    String newStr = "";
    int splitIndex = 0;
    for (int i = 0; i < str.length(); i++) {
        if (str.charAt(i) != ' ') {     
            newStr = newStr + str.charAt(i);   //Keep adding chars until you find a space
            if (newStr.length() > n) {   //If newStr's length exceeds 'n', break the loop
                break;
            }
        } else {
            splitIndex = i;    //Store the last space index 
            newStr = newStr + ' ';
        }
    }
    System.out.println(str.substring(0, splitIndex).trim());  //Use the splitIndex to print a substring
    System.out.println(str.substring(splitIndex, str.length()).trim());
}