Question

我的表格（Mysql）：

行动者：

CREATE TABLE `actors` (
 `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
 `name` varchar(255) NOT NULL,
 `active` tinyint(1) NOT NULL
);

影：

CREATE TABLE `movies` (
 `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
 `name` varchar(255) NOT NULL
);

Actor_Movie：

CREATE TABLE `actor_movie` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `actor_id` int(10) unsigned NOT NULL,
  `movie_id` int(10) unsigned NOT NULL,
  KEY `actor_movie_actor_id_foreign` (`actor_id`),
  KEY `actor_movie_movie_id_foreign` (`movie_id`),
  CONSTRAINT `actor_movie_actor_id_foreign` FOREIGN KEY (`actor_id`)  
  REFERENCES `actors` (`id`) ON DELETE CASCADE,
  CONSTRAINT `actor_movie_movie_id_foreign` FOREIGN KEY (`movie_id`) 
  REFERENCES `movies` (`id`) ON DELETE CASCADE
);

电影模特：

...
public function actors() {
   return $this->belongsToMany('App\Actor');
}

演员模特：

...
public function movies() {
    return $this->belongsToMany('App\Movie');
}

使用演员获取电影的实际查询：

$movies = Movie::with('actors')->get();

结果为JSON：

movies: [{
  id: 1,
  name: 'movie1',
  actors: [{ id: 1, name: 'actor1' }, { id: 2, name: 'actor2' }]
}, {
  id: 2,
  name: 'movie2',
  actors: [{ id: 1, name: 'actor1' }, { id: 3, name: 'actor3' }]
}...]

任何解决方案都可以使用Laravel集合或Mysql查询来与他们的演员一起获得多部电影。通过上面的查询，我得到每部电影的演员，但我想获得多部电影/演员，例如，第一张唱片将是演员1和演员2扮演同一部电影movie1和movie2等。

['movie1', 'movie2'] => ['actor1', 'actor2']
['movie1', 'movie3'] => ['actor1', 'actor3']
['movie4', 'movie5', 'movie6'] => ['actor4"]
etc...

谢谢。

Laravel多对多渴望加载

0 个答案: