我有一本字典词典:
Dictionary<string, Dictionary<char, string>> myDict;
我试图通过覆盖to string方法输出其内容,但我无法弄清楚如何将其转换为字符串。
我试过了:
StringBuilder str = new StringBuilder();
foreach (Dictionary<string, Dictionary<char, string>> s in str)
{
myDict.Append(s.Keys).Append(",").Append(s.Values);
}
这不起作用
答案 0 :(得分:3)
您的版本会尝试打印s.Keys
和s.Values
,它们都是集合。您可以使用循环打印它们,但您可以使用string.Join
两次:
public override string ToString() {
return string.Join(
",",
myDict.Select(
p => string.Format(
"{0}:{1}",
p.Key,
string.Join(",", p.Value.Select(x => string.Format("{0}={1}", x.Key, x.Value)))
)
);
}
注1:以上语法在两次调用中都使用string.Format
,而不是string interpolation。如果您使用的是较新版本的C#,则可以将其重写为更短的代码,例如
string.Join(",", p.Value.Select(x => $"{x.Key}={x.Value}"))
注2:对于旧版本的.NET,在两者选择后添加ToArray()
:
return string.Join(
",",
myDict.Select(
p => string.Format(
"{0}:{1}",
p.Key,
string.Join(",", p.Value.Select(x => string.Format("{0}={1}", x.Key, x.Value)).ToArray())
).ToArray()
));
答案 1 :(得分:2)
考虑使用Newtonsoft.Json
,它支持将字典序列化为字符串。
var values = new Dictionary<string, IDictionary<char, string>>
{
{
"test", new Dictionary<char, string>
{
['a'] = "apple",
['b'] = "banana",
['c'] = "cat"
}
},
{
"lights", new Dictionary<char, string>
{
['c'] = "compact fluorescent",
['l'] = "light emitting diode",
['i'] = "incandescent"
}
}
};
Console.WriteLine(JsonConvert.SerializeObject(values));
输出:
{“test”:{“a”:“apple”,“b”:“banana”,“c”:“cat”},“lights”:{“c”:“compact fluorescent”,“l “:”发光二极管“,”i“:”白炽灯“}}
答案 2 :(得分:0)
试试这个:
StringBuilder str = new StringBuilder();
foreach (var s in myDict)
{
foreach (var i in s.Value)
{
//Key is char, Value is string
str.Append("(")
.Append(s.Key)
.Append(",")
.Append(i.Key)
.Append(",")
.Append(i.Value)
.Append("),");
}
}
//remove trailing ","
var s = str.ToString().Trim(",");