Question

我想保存微调器值并检索所选项的值问题是我有一个整数旋转器和两个旋转器长而且我不知道如何使用这种方法获得长期值我想让这个方法能够以相同的方法设置整数和长期，并且我将这些val保存到sp，并获得它

private void spinnerVal(int spinnerID, int move, int selection){
Spinner sp = (Spinner) findViewById(spinnerID);
ArrayList<Integer> spinnerOption = new ArrayList<>();
for (int i = 0; i < 50; i+=move) {
    spinnerOption.add(i);
}
ArrayAdapter<Integer> integerArrayAdapter = new ArrayAdapter<>(this, R.layout.spinner_item, spinnerOption);
integerArrayAdapter.setDropDownViewResource(R.layout.support_simple_spinner_dropdown_item);
sp.setAdapter(integerArrayAdapter);
sp.setSelection(selection);
sp.setOnItemSelectedListener(this);

}

这是我的项目选择方法

    @Override
public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
    Editor editor;
    switch (parent.getId()) {
        case R.id.spinner1 /*2131492981*/:
            myServer.counter1 = Integer.valueOf(parent.getItemAtPosition(position).toString());
            editor = PreferenceManager.getDefaultSharedPreferences(this).edit();
            editor.putInt("counter1", myServer.counter1);
            editor.apply();
            return;
        case R.id.spinner2 /*2131492983*/:
            myServer.counter2 = (long) (Integer.valueOf(parent.getItemAtPosition(position).toString()) * 1000);
            editor = PreferenceManager.getDefaultSharedPreferences(this).edit();
            editor.putLong("counter2", myServer.counter2);
            editor.apply();
            return;
        case R.id.spinner3 /*2131492985*/:
            myServer.counter3 = (long) (Integer.valueOf(parent.getItemAtPosition(position).toString()) * 1000);
            editor = PreferenceManager.getDefaultSharedPreferences(this).edit();
            editor.putLong("counter3", myServer.counter3);
            editor.apply();
            return;
        default:
            return;

    }

}

Answer 1

当Integer.valueOf()项为Long时，您正在使用Spinner来解析Long值。您必须使用Long.parseLong()或Long.valueOf()来解析Long个项目。

保存并获取微调器项目

1 个答案: