Question

我正在尝试根据其中一列中的子字符串过滤python数据框。

如果ID字段的第13位和第14位的数字是＆lt; = 9，我想保留该行，如果它是＆gt; 9，我想放弃这一行。

示例：

ABCD-3Z-A93Z-01A-11R-A37O-07 - ＆gt;保持

ABCD-3Z-A93Z-11A-11R-A37O-07 - ＆gt;降

我已经设法达到以下解决方案，但我认为必须有一种更快，更有效的方法。

import pandas as pd

# Enter some data. We want to filter out all rows where the number at pos 13,14 > 9
df = {'ID': ['ABCD-3Z-A93Z-01A-11R-A37O-07', 'ABCD-6D-AA2E-11A-11R-A37O-07', 'ABCD-6D-AA2E-01A-11R-A37O-07',
             'ABCD-A3-3307-01A-01R-0864-07', 'ABCD-6D-AA2E-01A-11R-A37O-07', 'ABCD-6D-AA2E-10A-11R-A37O-07',
             'ABCD-6D-AA2E-09A-11R-A37O-07'],
      'year': [2012, 2012, 2013, 2014, 2014, 2017, 2015]
}
# convert to df
df = pd.DataFrame(df)

# define a function that checks if position 13&15 are > 9.
def filter(x):
    # that, if x is a string,
    if type(x) is str:
        if int(float(x[13:15])) <= 9:
            return True
        else:
            return False
    else:
        return False

# apply function
df['KeepRow'] = df['ID'].apply(filter)
print(df)

# Now filter out rows where "KeepRow" = False
df = df.loc[df['KeepRow'] == True]
print(df)
# drop the column "KeepRow" as we don't need it anymore
df = df.drop('KeepRow', axis=1)
print(df)

Answer 1

我认为您可以根据字符串的第13个符号进行过滤：

将pandas导入为pd

# Enter some data. We want to filter out all rows where the number at pos 13,14 > 9
df = pd.DataFrame({
    'ID': ['ABCD-3Z-A93Z-01A-11R-A37O-07',
           'ABCD-6D-AA2E-11A-11R-A37O-07',
           'ABCD-6D-AA2E-01A-11R-A37O-07',
           'ABCD-A3-3307-01A-01R-0864-07',
           'ABCD-6D-AA2E-01A-11R-A37O-07',
           'ABCD-6D-AA2E-10A-11R-A37O-07',
           'ABCD-6D-AA2E-09A-11R-A37O-07'],
    'year': [2012, 2012, 2013, 2014, 2014, 2017, 2015]
})
# convert to df

df['KeepRow'] = df['ID'].apply(lambda x: x[13] == '0')

或简单地说：

df[df['ID'].apply(lambda x: x[13] == '0')]

Answer 2

按位置使用indexing with str，然后转换为float并按boolean indexing过滤：

df = df[df['ID'].str[13:15].astype(float) <=9]
print(df)
                             ID  year
0  ABCD-3Z-A93Z-01A-11R-A37O-07  2012
2  ABCD-6D-AA2E-01A-11R-A37O-07  2013
3  ABCD-A3-3307-01A-01R-0864-07  2014
4  ABCD-6D-AA2E-01A-11R-A37O-07  2014
6  ABCD-6D-AA2E-09A-11R-A37O-07  2015

详情：

print(df['ID'].str[13:15])
0    01
1    11
2    01
3    01
4    01
5    10
6    09
Name: ID, dtype: object

Python，Pandas：基于函数过滤数据帧行

2 个答案: