Question

我在下面的代码中，我有一个由三个字段和两个按钮组成的表单。在Review按钮中，我想用阿拉伯语随机显示任何单词，并让用户通过勾选Show translation按钮以英语显示其翻译。

<html>
<body>

<script>
    function myFun1(var) {
        document.getElementById("demo").innerHTML = "The translation in English is  " + var;
    }        
</script>

<?php
    if ($_SERVER["REQUEST_METHOD"] == "POST") {
        $english = $_POST["english"];
        $arabic = $_POST["arabic"];
        $example = $_POST["example"];
    }
?>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
    <textarea name="english" rows="4" cols="70" placeholder="English">English</textarea>
    <br>
    <textarea name="arabic" rows="4" cols="70" placeholder="Arabic">Arabic</textarea>
    <br>
    <textarea name="example" rows="4" cols="70" placeholder="Example">Example</textarea>

    <br><br>

    <input type="submit" name="add" value="Add new">
    <input type="submit" name="review" value="Review">

    <br>

    <p id="demo"></p>
</form>

<?php

$servername = "localhost";
$username = "xxx";
$password = "yyy";
$dbname = "vdb";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

if (isset($_POST['add'])) {
    $sql = "INSERT INTO Vocabulary (English, Arabic, Example)
    VALUES ('$english', '$arabic', '$example')";

    if ($conn->query($sql) === TRUE) {
        echo "New record created successfully";
    } else {
        echo "Error: " . $sql . "<br>" . $conn->error;
    }
}
elseif (isset($_POST['review'])) {
    $sql = "SELECT COUNT(ID) as total FROM Vocabulary";
    $result = $conn->query($sql);
    $row = $result->fetch_assoc();
    #echo $row['total'];

    $generated = rand(1,$row['total']);

    $sql1 = "SELECT * FROM Vocabulary where ID = $generated";
    $result1 = $conn->query($sql1);
    $row1 = $result1->fetch_assoc();

    echo "<br>";
    echo $row1['Arabic'];

    echo "<br><br>";

    $eng = $row1['English'];

    echo '<button onClick = "myFun('.$eng.')">Show translation</button>';

}

$conn->close();
?>

</body>
</html>

在代码中，以下行创建按钮并触发myFun1()功能：

echo '<button onClick = "myFun('.$eng.')">Show translation</button>';

问题是当单击按钮时，没有任何反应（根本不显示该消息）。任何想法如何解决它？

Answer 1

首先将参数 var 更改为另一个参数名称，因为 var 是javascript中的关键字

 <script type="text/javascript">
        function myFun(as) {
            document.getElementById("demo").innerHTML = "The translation in English is  " + as;
        }        
 </script>

其次，您必须在单引号或双引号中传递字符串值以使用反斜杠\并从 myFun()中纠正函数名称到 myFun1()

echo '<button onClick = "myFun1(\''.$eng.'\')">Show translation</button>';

让你的代码完美无缺。

Answer 2

你有函数myFun1（var）的定义，但是你正在调用myFun（）。我想这就是为什么单击按钮后没有任何内容的原因。

Answer 3

在

之前将其添加到顶部

＆LT; html＆gt;标签

<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
    $english = $_POST["english"];
    $arabic = $_POST["arabic"];
    $example = $_POST["example"];
}
?>

将PHP参数传递给JavaScript函数时出现问题

3 个答案: