Question

我正在尝试使用偶数和奇数定义来加密我的消息。函数def swap_letters(message)就是我正在使用的函数：

我通过“＆＃34; message = message +＆＃39; x＆＃39;＆＃34;＆＃39;＆＃39;;循环遍历奇数和偶数字母列表。
然后，我使用"for counter in range(0, int(len(message)/2)): ...;
最后，我使用"letter_1.append(even_letters[counter])...

我通过加入new_message创建letter_1然后将其返回

我犯了什么错误，如何修复此代码以使其正常运行？

import tkinter as Tk 
from tkinter import messagebox, simpledialog, Tk

def is_even(number):
    return number % 2 == 0

def get_even_letters(message):
    even_letters = []
    for counter in range(0, len(message)):
        if is_even(counter):
            even_letters.append(message[counter])


def get_odd_letters(message):
    odd_letters = []
    for counter in range(0, len(message)):
        if not is_even(counter):
            odd_letters.append(message[counter])
    return odd_letters

def swap_letters(message):
    letter_1 = []
    if not is_even(len(message)):
        message = message + 'x'
    even_letters = get_even_letters(message)
    odd_letters = get_odd_letters(message)
    for counter in range(0, int(len(message)/2)):
        letter_1.append(odd_letters[counter])
        letter_1.append(even_letters[counter])
    new_message = ''.join(letter_1)
    return new_message

def get_message():
    message = simpledialog.askstring('Message', 'Enter the secret here: ')
    return message

def get_task():
    task = simpledialog.askstring('Task', 'Do you want to encrypt or decrypt?')
    return task

root = Tk()

while True:
    task = get_task()
    if task == 'encrypt':
        message = get_message()
        encrypted = swap_letters(message)
        messagebox.showinfo('Ciphertext of the secret message is:', encrypted)
    elif task == 'decrypt':
        message = get_message()
        decrypted = swap_letters(message)
        messagebox.showinfo('Plaintext of the secret message is:', decrypted)
    else:
        break
root.mainloop()

这是我得到的错误：

    Traceback (most recent call last):
  File "T:\Sublime Text 3\shhhhh.py", line 47, in <module>
    encrypted = swap_letters(message)
  File "T:\Sublime Text 3\shhhhh.py", line 29, in swap_letters
    letter_1.append(even_letters[counter])

TypeError: 'NoneType' object is not subscriptable
[Finished in 21.2s with exit code 1]
[shell_cmd: python -u "T:\Sublime Text 3\shhhhh.py"]
[dir: T:\Sublime Text 3]
[path: C:\Program Files (x86)\Python36-32\Scripts\;C:\Program Files `(x86)\Python36-32\;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\WINDOWS\System32\WindowsPowerShell\v1.0\;C:\Program Files (x86)\NVIDIA Corporation\PhysX\Common;C:\Program Files\dotnet\;C:\Program Files\Microsoft SQL Server\130\Tools\Binn\;C:\Program Files (x86)\Xoreax\IncrediBuild;C:\Users\mwliv\AppData\Local\Microsoft\WindowsApps;]`

Answer 1

您的get_even_letters函数未明确返回任何内容，因此它会隐式返回None，从而导致您稍后看到的错误。添加return语句应解决问题：

def get_even_letters(message):
    even_letters = []
    for counter in range(0, len(message)):
        if is_even(counter):
            even_letters.append(message[counter])

    return even_letters # Here!

Answer 2

只需修改您的代码，如下所示： -

for counter in range(0, int(len(message)/2)):
    # You need to verify whether values are None type or not before calling append 
    if(odd_letters != None):
        letter_1.append(odd_letters[counter])
    if(even_letters != None):
        letter_1.append(even_letters[counter])

Python - 消息加密返回`NoneType`错误

2 个答案: