我正在为我的Android应用程序开发一个简单的SQLite数据库。我跟着this tutorial。使用本教程我试图在我的数据库中添加三个字符串值,即“name”,“adress”和“phonenumber”。
这是DatabaseHandler.java的代码
// Database Version
private static final int DATABASE_VERSION = 1;
// Database Name
private static final String DATABASE_NAME = "favouritesmanager";
// Contacts table name
private static final String TABLE_CONTACTS = "favourites";
// Contacts Table Columns names
private static final String KEY_ID = "id";
private static final String KEY_NAME = "name";
private static final String KEY_PH_NO = "phone_number";
private static final String KEY_ADRESS = "adress";
public DatabaseHandler(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
// Creating Tables
@Override
public void onCreate(SQLiteDatabase db) {
String CREATE_CONTACTS_TABLE = "CREATE TABLE " + TABLE_CONTACTS + "("
+ KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT,"
+ KEY_PH_NO + " TEXT" + KEY_ADRESS + " TEXT" + ")";
db.execSQL(CREATE_CONTACTS_TABLE);
}
// Upgrading database
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// Drop older table if existed
db.execSQL("DROP TABLE IF EXISTS " + TABLE_CONTACTS);
// Create tables again
onCreate(db);
}
// Adding new contact
public void addContact(Contact contact) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(KEY_NAME, contact.getName()); // Contact Name
values.put(KEY_PH_NO, contact.getPhoneNumber()); // Contact Phone Number
values.put(KEY_ADRESS, contact.getAdress()); //address
// Inserting Row
db.insert(TABLE_CONTACTS, null, values); << Error here
db.close(); // Closing database connection
}
// Getting single contact
Contact getContact(int id) {
SQLiteDatabase db = this.getReadableDatabase();
Cursor cursor = db.query(TABLE_CONTACTS, new String[] { KEY_ID,
KEY_NAME, KEY_PH_NO }, KEY_ID + "=?",
new String[] { String.valueOf(id) }, null, null, null, null);
if (cursor != null)
cursor.moveToFirst();
Contact contact = new Contact(Integer.parseInt(cursor.getString(0)),
cursor.getString(1), cursor.getString(2), cursor.getString(3));
// return contact
return contact;
}
// Getting All Contacts
public List<Contact> getAllContacts() {
List<Contact> contactList = new ArrayList<Contact>();
// Select All Query
String selectQuery = "SELECT * FROM " + TABLE_CONTACTS;
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(selectQuery, null);
// looping through all rows and adding to list
if (cursor.moveToFirst()) {
do {
Contact contact = new Contact();
contact.setID(Integer.parseInt(cursor.getString(0)));
contact.setName(cursor.getString(1));
contact.setPhoneNumber(cursor.getString(2));
contact.setAdress(cursor.getString(3));
// Adding contact to list
contactList.add(contact);
} while (cursor.moveToNext());
}
// return contact list
return contactList;
}
}
和Contact.java类
public class Contact {
int _id;
String _name;
String _phone_number;
String _adress;
public Contact(){
}
// constructor
public Contact(int id, String name, String _phone_number, String adress){
this._id = id;
this._name = name;
this._phone_number = _phone_number;
this._adress = adress;
}
// constructor
public Contact(String name, String _phone_number, String adress){
this._name = name;
this._phone_number = _phone_number;
this._adress = adress;
}
// getting ID
public int getID(){
return this._id;
}
// setting id
public void setID(int id){
this._id = id;
}
// getting name
public String getName(){
return this._name;
}
// setting name
public void setName(String name){
this._name = name;
}
// getting phone number
public String getPhoneNumber(){
return this._phone_number;
}
// setting phone number
public void setPhoneNumber(String phone_number){
this._phone_number = phone_number;
}
//getting adress
public String getAdress(){
return this._adress;
}
//setting adress
public void setAdress(String adresstowrite){
this._adress = adresstowrite;
}
}
以下是我将数据放入数据库的代码
DatabaseHandler db = new DatabaseHandler(this);
db.addContact(new Contact(registeredname,registerdphone,adress )); << Error here
所有这三个变量都是字符串。
但是当我运行应用程序并检查Android监视器时,它显示以下错误
E/SQLiteDatabase: Error inserting name=yy adress=checking adress phone_number=08335565
android.database.sqlite.SQLiteException: table favourites has no column named adress (code 1): , while compiling: INSERT INTO favourites(name,adress,phone_number) VALUES (?,?,?)
at android.database.sqlite.SQLiteConnection.nativePrepareStatement(Native Method)
at android.database.sqlite.SQLiteConnection.acquirePreparedStatement(SQLiteConnection.java:908)
at android.database.sqlite.SQLiteConnection.prepare(SQLiteConnection.java:509)
at android.database.sqlite.SQLiteSession.prepare(SQLiteSession.java:588)
at android.database.sqlite.SQLiteProgram.<init>(SQLiteProgram.java:58)
at android.database.sqlite.SQLiteStatement.<init>(SQLiteStatement.java:31)
at android.database.sqlite.SQLiteDatabase.insertWithOnConflict(SQLiteDatabase.java:1527)
at android.database.sqlite.SQLiteDatabase.insert(SQLiteDatabase.java:1399)
at digiart.mapwithfirebase.DatabaseHandler.addContact(DatabaseHandler.java:67) // here
at digiart.mapwithfirebase.MapsActivity.favourite(MapsActivity.java:301) // and here
at java.lang.reflect.Method.invoke(Native Method)
at java.lang.reflect.Method.invoke(Method.java:372)
有人帮忙吗?
答案 0 :(得分:1)
async.filter
方法上的as any
创建脚本中存在错误(缺少逗号),并且未创建SQL
列。
onCreate
应该是:
KEY_ADRESS