Question

所以，我有这个练习，我必须从用户输入的坐标找到最近的药房，但我不知道如何。
我有来自每个药房的coodinates的文件，如下：

# Sub-programa
def fazTudo():
    dados = open("texto.txt", "r")
    linha = dados.readline()
    if linha == "":
        return "Arquivo de Farmácias está vazio!!!"
    else:
        for i in range(6):
            distancia = []
            vetor = dados.readline()
            x, y = vetor.split()
            distanciaX = x
            distanciaY = y
            distancia = distanciaX, distanciaY

# Programa Principal
entrada = (input().split(" "))
fazTudo()

当用户输入他的坐标（示例中为“20 88”）时，我应该告诉他最近的坐标。我会写我已经拥有的，但我的代码是巴西葡萄牙语，所以我希望你能帮助我。

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Answer 1

您现在所处的当前阶段似乎正在读取文件的距离。

从那里，你想要做的是找到用户输入的位置与每个药房的位置进行比较。找到X和Y坐标中的最小位移应该可以得到最近的药房。但是因为你想要距离，你需要通过获得绝对值来将位移值转换为距离。

这是我想到的解决方案：

# Find the closest distance to the pharmacies from a text file.
def closest_distance(raw_input_location):
    nearest_pharmacy = [0, 0]

    user_x_y = raw_input_location.split(" ")

    with open("filename.txt") as f:
        locations = f.read().splitlines()

    if not locations:
        return "Pharmacy list is empty!!!"
    else:
        for index, row in enumerate(locations):
            x_y = row.split(" ")
            delta_x = abs(int(user_x_y[0]) - int(x_y[0]))
            delta_y = abs(int(user_x_y[1]) - int(x_y[1]))
            if index == 0:
                nearest_pharmacy[0] = delta_x
                nearest_pharmacy[1] = delta_y
            elif delta_x < nearest_pharmacy[0] & delta_y < nearest_pharmacy[0]:
                nearest_pharmacy[0] = delta_x
                nearest_pharmacy[1] = delta_y
    # Returns the distance required to goto the closest pharmacy
    return str(nearest_pharmacy[0]) + " " + str(nearest_pharmacy[1])

# Prints out the closest distance from the inputted location
print(closest_distance("20 88"))

比较两个数组并找到最近的结果

1 个答案: