Question

我正在尝试通过读取字符串每个符号来识别字符串文字。我的扫描仪骨架的示例：

public sealed class Scanner
{        
    // some class inner implementations        
    /// <summary>
    /// 
    /// </summary>
    /// <param name="Line"></param>
    /// <param name="LineNumber"></param>
    public void Run(String Line, Int32 LineNumber)
    {
        var ChPosition = default(Int32);
        var ChCurrent  = default(Char);
        var Value      = new StringBuilder();

        while (default(Char) != Line.ElementAtOrDefault<Char>(ChPosition))
        {
            ChCurrent = Line.ElementAtOrDefault<Char>(ChPosition);

            #region [Whitespace]
            if (Char.IsWhiteSpace(ChCurrent))
            {
                ChPosition++;
            }
            #endregion
            else
            {
                switch (ChCurrent)
                {                        
                    #region [String Literal (")]
                    case '"':
                        {
                            // skipping " sign, include only string inner value
                            ChCurrent = Line.ElementAtOrDefault<Char>(++ChPosition);

                            // ...? Problematic place!!!

                            this.Tokens.Enqueue(new SharedEntities.Token
                            {
                                Class = SharedEntities.Token.TokenClass.StringLiteral,
                                Value = Value.ToString()
                            }
                            );
                            Value.Clear();
                            ChPosition++;
                            break;
                        }
                    #endregion                        
                        {
                            throw new ScanningException(
                            "<syntax_error#" + ChCurrent.ToString() + ">\n"
                            + "Unsupported character appeared at: {ln: "
                            + LineNumber.ToString()
                            + "; pos: "
                            + (ChPosition + 1).ToString()
                            + "}"
                            );
                        }
                } // [switch(ChCurrent)]                   
            } // [if(Char.IsWhiteSpace(ChCurrent))...else]
        } // [while(default(Char) != Line.ElementAtOrDefault<Char>(ChPosition))]
    } // [public void Run(String Line, Int32 LineNumber)]
} // [public sealed class Scanner]

我的目标是解析类似pascal的字符串：“{所有内容，但”，仅“”对是允许}”。

Answer 1

首先，您显然正在使用某种解析库，如果您修改了代码，则会有更好的机会，例如：像我一样，所以任何人都可以复制，粘贴，运行你的代码。

答案很简单，你的（字符串文字） - 分析区域不会解析所有输入。以下是您修改的代码，无需任何其他库即可使用：

public class Test
{
    static char ElementAtOrDefault(string value, int position)
    {
        return position >= value.Length ? default(char) : value[position];
    }
    static string parseStringLiteral(string value, ref int ChPosition)
    {
        StringBuilder Value = new StringBuilder();
        char ChCurrent = ElementAtOrDefault(value, ++ChPosition);
        while (ChCurrent != '"')
        {
            Value.Append(ChCurrent);
            ChCurrent = ElementAtOrDefault(value, ++ChPosition);
            if (ChCurrent == '"')
            {
                // "" sequence only acceptable
                if (ElementAtOrDefault(value, ChPosition + 1) == '"')
                {
                    Value.Append(ChCurrent);
                    // skip 2nd double quote
                    ChPosition++;
                    // move position next
                    ChCurrent = ElementAtOrDefault(value, ++ChPosition);
                }
            }
            else if (default(Char) == ChCurrent)
            {
                // message: unterminated string
                throw new Exception("ScanningException");
            }
        }
        ChPosition++;
        return Value.ToString();
    }

    public static void test(string literal)
    {
        Console.WriteLine("testing literal with " + literal.Length + 
            " chars:\n" + literal);
        try
        {
            int pos = 0;
            string res = parseStringLiteral(literal, ref pos);
            Console.WriteLine("Parsed " + res.Length + " chars:\n" + res);
        }
        catch (Exception ex)
        {
            Console.WriteLine("Error: " + ex.Message);
        }
        Console.WriteLine();
    }

    public static int Main(string[] args)
    {
        test(@"""Hello Language Design""");
        test(@"""Is there any problems with the """"strings""""?""");
        test(@"""v#:';?325;.<>,|+_)""(*&^%$#@![]{}\|-_=""");
        return 0;
    }
}

运行此程序会产生输出：

testing literal with 23 chars:
"Hello Language Design"
Parsed 21 chars:
Hello Language Design

testing literal with 45 chars:
"Is there any problems with the ""strings""?"
Parsed 41 chars:
Is there any problems with the "strings"?

testing literal with 39 chars:
"v#:';?325;.,|+_)"(*&^%$#@![]{}\|-_="
Parsed 18 chars:
v#:';?325;.,|+_)

因此它适用于您的测试，但算法不正确，请尝试运行：

//literal with "", should produce ", but it does not
test(@"""""""""");

你会错误地得到：

testing literal with 4 chars:
""""
Parsed 0 chars:

问题是，如果你遇到“在你的状态下你的角色，你不会检查下一个角色，如果是的话”：

while (ChCurrent != '"') //bug

当然，我为您创建了正确的版本:-) 它是（它使用你的风格，只是你的编辑版本）：

static string parseStringLiteral(string value, ref int ChPosition)
{
    StringBuilder Value = new StringBuilder();
    char ChCurrent = ElementAtOrDefault(value, ++ChPosition);
    bool goon = true;
    while (goon)
    {
        if (ChCurrent == '"')
        {
            // "" sequence only acceptable
            if (ElementAtOrDefault(value, ChPosition + 1) == '"')
            {
                Value.Append(ChCurrent);
                // skip 2nd double quote
                ChPosition++;
                // move position next
                ChCurrent = ElementAtOrDefault(value, ++ChPosition);
            }
            else goon = false; //break;
        }
        else if (default(Char) == ChCurrent)
        {
            // message: unterminated string
            throw new Exception("ScanningException");
        }
        else
        {
            Value.Append(ChCurrent);
            ChCurrent = ElementAtOrDefault(value, ++ChPosition);
        }
    }
    ChPosition++;
    return Value.ToString();
}

快乐编码： - ）

字符串文字识别问题

1 个答案: