Question

我在根据数据库结构将数据插入数据库时遇到问题。我有3张桌子。 Company table Users table branches table。

现在这就是我如何建立这些表之间的关系。

公司表和用户表具有一对多的关系

公司表和分支表具有一对多的关系

分支表和用户表有一对多关系

这就是我的模型的样子

PS ：我只是数据库和laravel的初学者

公司模式

public function branches()
  {
      return $this->hasMany('App\Branch');
  }

  public function users()
  {
      return $this->hasMany('App\User');
  }

用户模型

 public function company()
    {
        return $this->belongsTo('App\Company')
        ->withTimestamps();
    }

     public function branches()
    {
        return $this->belongsTo('App\Branch')
        ->withTimestamps();
    }

分支模型

public function company()
    {
     return $this->belongsTo('App\Company');

    }

    public function users()
  {
      return $this->hasMany('App\User');
  }

现在，当用户注册时，只有公司表中填充了详细信息，但用户表和分支表未填充，我收到错误

"SQLSTATE[HY000]: General error: 1364 Field 'company_id' doesn't have a default value (SQL: insert into `branches` (`name`, `updated_at`, `created_at`) values (Virginia, 2017-10-14 03:19:38, 2017-10-14 03:19:38)) ◀"

这就是我在RegisterController中保存数据的方法

RegisterController

protected function create(array $data)
    {
        return User::create([
            'name' => $data['name'],
            'email' => $data['email'],
            'phone' => $data['phone'],
            'password' => bcrypt($data['password']),

            "company_id" => Company::create(
                [
                    "name" => $data['rname'],
                    "email" => $data['remail'],
                    "phone" => $data['rphone'],
                    "address" => $data['raddress']           

                ]
           )->id,

            "branch_id" => Branch::create (
                   [
                       "name" => $data['rbranch']
                   ]
               )->id   


        ]);

    }

Answer 1

您需要创建可以为空的外键...

在迁移中，使用 - ＆gt; nullable（）函数...

$table->integer('company_id')->unsigned()->nullable();

这将让你最初不包括company_id，值将为null ...如果没有nullable（），数据库将不允许空值......

希望这有帮助。

Answer 2

您应该尝试这可能对您有所帮助：

protected function create(array $data)
{
    $company =  Company::create(
            [
                "name" => $data['rname'],
                "email" => $data['remail'],
                "phone" => $data['rphone'],
                "address" => $data['raddress']           

            ]);

更新了答案

    $branch = Branch::create (
               [
                   "name" => $data['rbranch'],
                   "company_id" => $company->id
               ]
           );

    if(isset($company->id) && isset($branch->id)){
      return User::create([
          'name' => $data['name'],
          'email' => $data['email'],
          'phone' => $data['phone'],
          'password' => bcrypt($data['password']),

          "company_id" => $company->id,

          "branch_id" => $branch->id   


      ]);
    } else{
        return redirect()->back()->withFlashDanger("company or branch no successfully insterted");

    }

}

数据库与Laravel的关系

2 个答案: