请帮助我理解这种方法的Javadocs。第二个参数如何影响返回的上下文?
这是一种相对于加载类路径资源的便捷方法 给定的类。为了充分灵活,请考虑使用a 带有XmlBeanDefinitionReader和a的GenericApplicationContext ClassPathResource参数。
答案 0 :(得分:0)
Class<?>
是使用未绑定通配符的泛型类型。对于某种类型的Foo来说,它意味着“Class<Foo>
”。 ClassPathXmlApplicationContext 构造函数参数clazz使类加载资源(给定路径的基础)。
/**
* Create a new ClassPathXmlApplicationContext, loading the definitions
* from the given XML file and automatically refreshing the context.
* <p>This is a convenience method to load class path resources relative to a
* given Class. For full flexibility, consider using a GenericApplicationContext
* with an XmlBeanDefinitionReader and a ClassPathResource argument.
* @param path relative (or absolute) path within the class path
* @param clazz the class to load resources with (basis for the given paths)
* @throws BeansException if context creation failed
* @see org.springframework.core.io.ClassPathResource#ClassPathResource(String, Class)
* @see org.springframework.context.support.GenericApplicationContext
* @see org.springframework.beans.factory.xml.XmlBeanDefinitionReader
*/
public ClassPathXmlApplicationContext(String path, Class clazz) throws BeansException {
this(new String[] {path}, clazz);
}