Question

假设您以120美元的价格购买了一件家具，并且您将在未来的12个月内付款而无需付款。我正在尝试制作一个程序，告诉您未来12个月的每月付款情况。我制作的节目告诉你第一个月的每月付款/金额，但它只复制了所有12个月的第一个月，我想知道是否有人可以引导我朝着正确的方向，所以应付金额是正确的12个月。我知道我弄乱了某种方程式，但无法想出它。我在python上仍然很新，遇到了一些麻烦。这就是我所做的：

purchasePrice = input("Enter purchase price")
purchasePrice = int(purchasePrice)
month = 1
 while month <=12:
  print (month)
  month = month + 1
  monthlyPayment = purchasePrice/12
  amountDue = purchasePrice - monthlyPayment 
  print ("Monthly payment", monthlyPayment)
  print ("Amount due: ", amountDue)

我的输出是：

Enter purchase price 120
1
Monthly payment 10.0
Amount due:  110.0
2
Monthly payment 10.0
Amount due:  110.0
3
Monthly payment 10.0
Amount due:  110.0
4
Monthly payment 10.0
Amount due:  110.0

直到第12个月

Answer 1

问题是每次这条线都符文 amountDue = purchasePrice - monthlyPayment purchasePrice = 120和monthlyPayment = 10因此amountDue不会改变。您需要将月份乘以monthlyPayment，以查看您已支付每月付款的次数。并改变行的顺序，因为月份已经等于1.所以你的代码看起来像

purchasePrice = input("Enter purchase price")
purchasePrice = int(purchasePrice)
month = 1
while month <=12:
  print (month)
  monthlyPayment = purchasePrice/12
  amountDue = purchasePrice - monthlyPayment * month
  month = month + 1
  print ("Monthly payment", monthlyPayment)
  print ("Amount due: ", amountDue)

Answer 2

您有多个在循环内声明的变量。当你在循环中声明一个变量时，它会被破坏并覆盖循环的每次迭代。您希望声明循环的变量OUTSIDE以保留每次迭代的变量。

##Condensed two lines into one.
purchasePrice = int(input("Enter purchase price"))

#Variable declaration for preservation.
monthlyPayment = purchasePrice/12

##Changing from a while loop to a for loop lets us remove the month variable
for x in range(1, 13)
    print (x)
    print ("Monthly payment", monthlyPayment)
    ##Here we get rid of the amountDue variable and just perform the calculation in the output
    print ("Amount due: ", purchasePrice -((purchasePrice/12)*x))

现在基本表单正常工作，我们可以将代码压缩成更干净，代码更少的代码。

修订清洁表格：

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python中的每月付款

2 个答案: