Question

我需要删除训练零的数字，例如： 9.2500 = 9.25 感谢@Avinash Raj的上一篇文章，我发现了这个：

^(\d+\.\d*?[1-9])0+$

哪个适用于该应用程序。但是，在某些情况下，我有一个像11.0000的数字，上面的RegEx返回：

11.0

我需要回复：

我不确定如何在没有需要时删除小数和零？我花了一些时间试图解决这个问题，但我很难过。

Answer 1

试试这个：

var request = URLRequest(url: url)
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.httpMethod = "POST"
request.httpBody = "id=42".data(using: .utf8)

let task = URLSession.shared.dataTask(with: request) { data, response, error in
    // ...
}
task.resume()

Regex101 here

Answer 2

^(\d+(?:\.\d*?[1-9](?=0|\b))?)\.?0*$

演示here。

<强>解释

^         //Beginning of line
(         //Start collecting our group
\d+       //All digits before decimal
(?:       //START-Non collecting group
\.        //Decimal point
\d*?      //It should actually be [0-9]
[1-9]     //Last significant digit after decimal
(?=0|\b)  //Either should be followed by zero or END OF WORD
)?        //END-Non collecting group
          //The non-capturing group after decimal is optional
)         //End collecting our group
\.?       //Optional decimal (decimal collected if it wasn't used earlier)
0*        //All the remaining zeros no + as all digits might be significant that is no ending zero
$         //End of line.

Answer 3

试试这个

^\d*\.[1-9]*([0]+)*$

解释

^  beginning of the term
\d*  digits from 0-9 those can be any number (can be 0 number or more)
\.   escaping the .
[1-9]* numbers from 1 to 9 (can be 0 number or more)
([0]+)  capturing all 0s in group1
$  end of the term

Regex101 here

使用RegEx如何在需要时删除尾随零和小数

3 个答案: