Question

#Passwordgen
#Generate a password

def main():

    #Ask the user to input a long string of words, separated by spaces
    sent = input("Enter a sentance separated by spaces: ")

    #Ask the user to input a position within each word
    #Take the position of that word
    pos = eval(input("Input a position within each word: "))
    words = sent.split(" ")

    wordy = ""                                   
    #loops through the word to take the position of the letter
    for word in words:
        wordy = wordy + word[pos] 

    #Prints out the letters as a password
    print("Your password is: ", wordy)  


main()

我的教授希望我打印出从该短语生成的密码，用于从零开始到包括用户输入位置的每个位置。它应该使用密码（短语，位置）功能来生成密码。

使用字符串格式打印每个密码输出行，如下所示。

例如：

Enter words, separated by spaces: correct horse battery staple
Up to position within each word: 3

Password 0: chbs
Password 1: ooat
Password 2: rrta
Password 3: rstp

Answer 1

到目前为止，代码表现还不错，只需要进行一些调整：

#Passwordgen
#Generate a password

def main():

    #Ask the user to input a long string of words, separated by spaces
    sent = input("Enter a sentance separated by spaces: ")

    #Ask the user to input a position within each word
    #Take the position of that word
    pos = int(input("Input a position within each word: "))
    words = sent.split(" ")

    # set a counter variable to count each password generateed
    count = 0

    #loops through the word to take the position of the letter
    for p in range(pos+1):
        # reset wordy for each new password we are generating
        wordy = ""
        for word in words:
            wordy = wordy + word[p]
        #Prints out the letters as a password
        print("Your password {c} is: {pw}".format(c = count, pw = password))
        count += 1

main()

我们需要跟踪每个单词中我们从哪个位置开始的字母，这就是for p in range(pos+1)行的作用（我们pos+1来获取位置3+1（或4）因为范围达到但不包括该值。

另外，正如指示所示，我们需要"Use string formatting to print each of the password output lines"，因此，参考这些python3 format examples，我们可以格式化每个密码的输出以及相关的计数。

希望这有助于你，干杯！

使用python函数调整代码

1 个答案: