Question

我正在尝试使用一种方法创建一个小的asmx服务，该方法将返回一些虚拟数据。运行服务时出现以下错误：＆＃34; System.InvalidOperationException：System.Xml.XmlAttribute不能用作：＆＃39; xml元素＆＃39;。＆＃34;

我的网络方法如下：

[WebMethod]
public SubmitCaseRequestResponse1 SubmitCaseRequest(SubmitCaseRequestRequest1 request)
{

    var response = new SubmitCaseRequestResponse1
    {
        ResponseID = "456325898",
        Success = true,
        ValidationErrors = null

    };
    return response;
}

我的SubmitCaseRequestResponse1类：

public class SubmitCaseRequestResponse1

{ public string ResponseId {get;组; }

public bool Success { get; set; }

public ValidationError[] ValidationErrors { get; set; }

}

，请求类是：

public class SubmitCaseRequestRequest1

{ public AuthHeader AuthHeader {get;组; }

public SubmitCaseRequestRequest PostCaseDateRequest { get; set; }

}

Answer 1

我应该序列化复杂类型SubmitCaseRequestRequest1和SubmitCaseRequestResponse1。需要为复杂类型添加[XmlElement]，为简单类型添加[XmlAttribute]

[System.Xml.Serialization.XmlTypeAttribute(Namespace = "http://tempuri.org/")]
[Serializable]
public class SubmitCaseRequestRequest1
{
    [XmlElement]
    public AuthHeader AuthHeader { get; set; }

    [XmlElement]
    public SubmitCaseRequestRequest PostCaseDateRequest { get; set; }
}

[Serializable]
public class SubmitCaseRequestRequest
{
    [XmlElement]
    public Guid? RequestId { get; set; }
    [XmlAttribute]
    public string LCICourtNumber { get; set; }
    [XmlAttribute]
    public string CaseNumber { get; set; }
    [XmlAttribute]
    public string DebtorLastName { get; set; }
    [XmlAttribute]
    public string DateType { get; set; }
}

＆＃34; System.Xml.XmlAttribute不能用作：＆＃39; xml元素＆＃39;。＆＃34;在运行我的asmx服务时

1 个答案: