我有点像漫步者,但我会尽力保持清晰 -
我很无聊,所以我正在制作一个“shoutbox”,我对一件事感到有些困惑。我希望得到一条消息输入的时间,我想确保我得到服务器时间,或者至少确保我没有得到用户的本地时间。我知道这没关系,因为除了我之外,任何人都不会使用这个东西,但我想要彻底。我环顾四周并测试了一些东西,我认为这样做的唯一方法就是从?/?/ 1970或者其他任何东西获得毫秒数,因为对每个人来说都是一样的。
我这样做是这样的:
var time = new Date();
var time = time.getTime();
返回类似1294862756114
的数字。
有没有办法将1294862756114
转换为更易读的日期,例如DD/MM/YYYY HH:MM:SS
?
所以,基本上,我正在寻找JavaScript相当于PHP的date();
函数。
答案 0 :(得分:259)
var time = new Date().getTime();
var date = new Date(time);
alert(date.toString()); // Wed Jan 12 2011 12:42:46 GMT-0800 (PST)
答案 1 :(得分:144)
如果您想为自己的日期定制格式,我会为其提供a simple function:
var now = new Date;
console.log( now.customFormat( "#DD#/#MM#/#YYYY# #hh#:#mm#:#ss#" ) );
以下是支持的令牌:
token: description: example:
#YYYY# 4-digit year 1999
#YY# 2-digit year 99
#MMMM# full month name February
#MMM# 3-letter month name Feb
#MM# 2-digit month number 02
#M# month number 2
#DDDD# full weekday name Wednesday
#DDD# 3-letter weekday name Wed
#DD# 2-digit day number 09
#D# day number 9
#th# day ordinal suffix nd
#hhhh# 2-digit 24-based hour 17
#hhh# military/24-based hour 17
#hh# 2-digit hour 05
#h# hour 5
#mm# 2-digit minute 07
#m# minute 7
#ss# 2-digit second 09
#s# second 9
#ampm# "am" or "pm" pm
#AMPM# "AM" or "PM" PM
这是代码:
//*** This code is copyright 2002-2016 by Gavin Kistner, !@phrogz.net
//*** It is covered under the license viewable at http://phrogz.net/JS/_ReuseLicense.txt
Date.prototype.customFormat = function(formatString){
var YYYY,YY,MMMM,MMM,MM,M,DDDD,DDD,DD,D,hhhh,hhh,hh,h,mm,m,ss,s,ampm,AMPM,dMod,th;
YY = ((YYYY=this.getFullYear())+"").slice(-2);
MM = (M=this.getMonth()+1)<10?('0'+M):M;
MMM = (MMMM=["January","February","March","April","May","June","July","August","September","October","November","December"][M-1]).substring(0,3);
DD = (D=this.getDate())<10?('0'+D):D;
DDD = (DDDD=["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"][this.getDay()]).substring(0,3);
th=(D>=10&&D<=20)?'th':((dMod=D%10)==1)?'st':(dMod==2)?'nd':(dMod==3)?'rd':'th';
formatString = formatString.replace("#YYYY#",YYYY).replace("#YY#",YY).replace("#MMMM#",MMMM).replace("#MMM#",MMM).replace("#MM#",MM).replace("#M#",M).replace("#DDDD#",DDDD).replace("#DDD#",DDD).replace("#DD#",DD).replace("#D#",D).replace("#th#",th);
h=(hhh=this.getHours());
if (h==0) h=24;
if (h>12) h-=12;
hh = h<10?('0'+h):h;
hhhh = hhh<10?('0'+hhh):hhh;
AMPM=(ampm=hhh<12?'am':'pm').toUpperCase();
mm=(m=this.getMinutes())<10?('0'+m):m;
ss=(s=this.getSeconds())<10?('0'+s):s;
return formatString.replace("#hhhh#",hhhh).replace("#hhh#",hhh).replace("#hh#",hh).replace("#h#",h).replace("#mm#",mm).replace("#m#",m).replace("#ss#",ss).replace("#s#",s).replace("#ampm#",ampm).replace("#AMPM#",AMPM);
};
答案 2 :(得分:30)
您可以简单地使用Datejs库,以便将日期转换为所需的格式。
我经常参加考试,并且有效。
以下是一个说明如何实现这一目标的片段:
var d = new Date(1469433907836);
d.toLocaleString(); // expected output: "7/25/2016, 1:35:07 PM"
d.toLocaleDateString(); // expected output: "7/25/2016"
d.toDateString(); // expected output: "Mon Jul 25 2016"
d.toTimeString(); // expected output: "13:35:07 GMT+0530 (India Standard Time)"
d.toLocaleTimeString(); // expected output: "1:35:07 PM"
答案 3 :(得分:18)
以下是一个代码段,可让您将日期格式化为所需的输出:
var time = new Date();
var time = time.getTime();
var theyear = time.getFullYear();
var themonth = time.getMonth() + 1;
var thetoday = time.getDate();
document.write("The date is: ");
document.write(theyear + "/" + themonth + "/" + thetoday);
答案 4 :(得分:5)
尝试使用此代码:
var milisegundos = parseInt(data.replace("/Date(", "").replace(")/", ""));
var newDate = new Date(milisegundos).toLocaleDateString("en-UE");
享受它!
答案 5 :(得分:3)
尝试使用此代码:
var datetime = 1383066000000; // anything
var date = new Date(datetime);
var options = {
year: 'numeric', month: 'numeric', day: 'numeric',
};
var result = date.toLocaleDateString('en', options); // 10/29/2013
答案 6 :(得分:2)
试试这个:
var time = new Date().toJSON();
答案 7 :(得分:2)
一个行代码。
var date = new Date(new Date().getTime());
或
var date = new Date(1584120305684);
答案 8 :(得分:0)
使用datejs
new Date().toString('yyyy-MM-d-h-mm-ss');
答案 9 :(得分:0)
/Date(1383066000000)/
function convertDate(data) {
var getdate = parseInt(data.replace("/Date(", "").replace(")/", ""));
var ConvDate= new Date(getdate);
return ConvDate.getDate() + "/" + ConvDate.getMonth() + "/" + ConvDate.getFullYear();
}
答案 10 :(得分:0)
假设日期为毫秒日期为1526813885836
,因此您可以使用此示例代码以字符串形式访问日期:
console.log(new Date(1526813885836).toString());
清楚见下面的代码:
const theTime = new Date(1526813885836);
console.log(theTime.toString());