我有一个MySQL表，如下所示：
+-------------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-------------+---------+------+-----+---------+-------+
| person_id | int(11) | NO | MUL | NULL | |
| location_id | int(11) | NO | MUL | NULL | |
| date_signed | date | NO | | NULL | |
| date_ended | date | YES | | NULL | |
+-------------+---------+------+-----+---------+-------+
所有记录都是这样的：
+-----------+-------------+-------------+------------+
| person_id | location_id | date_signed | date_ended |
+-----------+-------------+-------------+------------+
| 1 | 49 | 2007-09-29 | NULL |
| 1 | 41 | 2010-10-09 | NULL |
| 2 | 45 | 2007-09-29 | NULL |
| 2 | 58 | 2007-12-16 | NULL |
| 3 | 49 | 2007-09-29 | NULL |
| 4 | 45 | 2007-09-29 | NULL |
| 4 | 35 | 2013-10-04 | NULL |
| 5 | 45 | 2007-09-29 | NULL |
| 5 | 37 | 2009-01-09 | NULL |
| 5 | 32 | 2009-10-08 | NULL |
+-----------+-------------+-------------+------------+
我正在尝试将每个人的date_ended更新为比该人的下一个时间顺序行中的date_signed少一天：
+-----------+-------------+-------------+------------+
| person_id | location_id | date_signed | date_ended |
+-----------+-------------+-------------+------------+
| 1 | 49 | 2007-09-29 | 2010-10-08 |
| 1 | 41 | 2010-10-09 | NULL |
| 2 | 45 | 2007-09-29 | 2007-12-15 |
| 2 | 58 | 2007-12-16 | NULL |
.
.
.
但我无法弄清楚如何选择下一个按时间顺序排列的记录。我尝试了类似问题的一些建议：
UPDATE a column based on the value of another column in the same table
Mysql - update table column from another column based on order
但我无法让他们工作。有没有办法在MySQL中做到这一点？